ÌâÄ¿ÄÚÈÝ
Ë®µÄÓ²¶È±íʾ·½·¨ÊÇ£º½«Ë®ÖеÄCa2+¡¢Mg2+ÖÊÁ¿ÕÛËã³ÉCaOµÄÖÊÁ¿¡£Í¨³£°Ñ1LË®Öк¬ÓÐ10mg CaO³ÆÎª1¶È£¬1LË®Öк¬ÓÐ20mg CaO¼´Îª2¶È£¬ÒÔ´ËÀàÍÆ¡£8¶ÈÒÔÉÏΪӲˮ£¬8¶ÈÒÔÏÂΪÈíË®¡£ÎÒ¹ú¹æ¶¨ÒûÓÃË®µÄÓ²¶È²»Äܳ¬¹ý25¶È¡£
£¨1£©ÈÕ³£Éú»îÖУ¬¿ÉÓà ¼ìÑéijˮÑùÊÇӲˮ»¹ÊÇÈíË®¡£
£¨2£©Ca(HCO3)2¼ÓÈÈʱ»á·Ö½â²úÉúÒ»ÖÖ°×É«³Áµí£¨Ë®¹¸µÄÖ÷Òª³É·Ö£©ºÍÁ½ÖÖ³£¼ûµÄÑõ»¯ÎÇëд³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£ºÓË®¡¢¾®Ë®ÖÐÈÜÓÐÒ»¶¨Á¿µÄCa(HCO3)2£¬ÒûÓÃǰ¿É²ÉÈ¡ µÄ·½·¨À´½µµÍË®µÄÓ²¶È¡£
£¨3£©¼ÒÓÃÈÈˮƿһµ©²úÉúË®¹¸£¬Æä±£ÎÂÐÔÄܻήµÍ¡£ÓÃÏ¡ÑÎËá¿É³ýÈ¥ÉÏÊöË®¹¸£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ ¡£
£¨4£©È¡Ä³Ë®Ñù1L£¬¾ÊµÑé²â¶¨£¬ÆäÖк¬Ca2+0.2g£¬´ËË®ÑùµÄÓ²¶ÈԼΪ £¬ ÊÇ·ñ·ûºÏÒûÓÃË®±ê×¼? ¡£
¢Å·ÊÔíË® ¢ÆCa(HCO3)2
CaCO3¡ý + H2O + CO2¡ü ; Öó·Ð
¢ÇCaCO3 + 2HCl == CaCl2 + H2O + CO2¡ü »ò Mg(OH)2 + 2HCl == MgCl2 + 2H2O
¢È 28 £»²»·ûºÏ