ÌâÄ¿ÄÚÈÝ

ÉÕ±­ÖÐ×°ÓÐÒ»¶¨Á¿ÁòËáºÍÁòËáÍ­µÄ»ìºÏÈÜÒº£¬ÒÑÖª¸ÃÈÜÒºÖк¬H2SO4µÄÖÊÁ¿Îª9.8 g¡£Ä³Í¬Ñ§Îª²â¶¨¸Ã»ìºÏÈÜÒºÖÐÁòËáÍ­µÄÖÊÁ¿£¬ÏòÉÕ±­ÖÐÖð½¥¼ÓÈë10%µÄNaOHÈÜÒº£¬µÃµ½³ÁµíµÄÖÊÁ¿¼Ç¼ÈçÏ£º

(1)µÃµ½³ÁµíµÄ×ÜÖÊÁ¿Îª___________g£¬¸Ã»ìºÏÈÜÒºÖÐÁòËáÍ­µÄÖÊÁ¿Îª___________g¡£

(2)²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿ÊǶàÉÙ¿Ë?(ÒªÇóд³ö¼ÆËã¹ý³Ì)

(3)»­³öÔڸûìºÏÈÜÒºÖмÓÈëNaOHÈÜÒºÖÊÁ¿ÓëÉú³É³ÁµíÖÊÁ¿±ä»¯¹ØÏµµÄÇúÏß¡£

(1)9.8    16.0

(2)½â£ºÉèÓëÁòËá·´Ó¦µÄNaOHµÄÖÊÁ¿Îªx£¬ÓëCuSO4·´Ó¦µÄNaOHµÄÖÊÁ¿Îªy¡£

H2SO4+2NaOH===Na2SO4+2H2O           CuSO4+2NaOH===Cu(OH)2+Na2SO4

  98      80                                    80       98

  9.8 g    x                                      y       9.8 g

                                    

x=8 g                                           y=8 g

¹Ê²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄÖÊÁ¿¹²Îª

´ð£ºÕû¸ö¹ý³ÌÖвμӷ´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿Îª160¿Ë¡£

(3)(ץסÆðµã¡¢Õ۵㼰ÇúÏß×ßÊÆ¸ø·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø