ÌâÄ¿ÄÚÈÝ
άÉúËØºÍÌÇÀà
άÉúËØºÍÌÇÀà
ÓªÑøËØ£»£¨2£©Ð¡ÂóÔÚÉú²ú¹ý³ÌÖг¤ÆÚÊ©ÓÃijÖÖµª·Ê£¬µ¼ÖÂÍÁÈÀËữºÍ°å½á£¬ÕâÖÖµª·ÊµÄ»¯Ñ§Ê½ÊÇ
£¨NH4£©2SO4
£¨NH4£©2SO4
£»£¨3£©ÕâÖÖµª·ÊÒ²²»ÄÜÓëÊìʯ»ÒÒ»ÆðÊ©Óã¬Óû¯Ñ§·½³Ìʽ±íʾÆäÔÒò
£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü
£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü
£®·ÖÎö£º£¨1£©¸ù¾ÝÊ߲˺ÍÃæ·ÛÖк¬ÓеÄÓªÑøËØ·ÖÎö£»
£¨2£©¸ù¾Ý³£¼ûµÄµª·Ê¶ÔÍÁÈÀµÄÓ°Ïì·ÖÎö£»
£¨3£©¸ù¾ÝÁòËáï§ÓëÊìʯ»ÒµÄ·´Ó¦Ð´³ö·´Ó¦µÄ·½³Ìʽ£®
£¨2£©¸ù¾Ý³£¼ûµÄµª·Ê¶ÔÍÁÈÀµÄÓ°Ïì·ÖÎö£»
£¨3£©¸ù¾ÝÁòËáï§ÓëÊìʯ»ÒµÄ·´Ó¦Ð´³ö·´Ó¦µÄ·½³Ìʽ£®
½â´ð£º½â£º£¨1£©ÔÚÊ߲˺ÍÃæ·ÛÖк¬ÓеÄÓªÑøËØÊÇάÉúËØºÍÌÇÀࣻ
£¨2£©µ¼ÖÂÍÁÈÀËữºÍ°å½áµÄµª·ÊÊÇÁòËáï§£¬»¯Ñ§Ê½ÊÇ£ºNH4£©2SO4£»
£¨3£©ÓÉÓÚÁòËáï§ÄÜÓëÊìʯ»ÒÄÜ·´Ó¦·Å³ö°±Æø£¬½µµÍ·ÊЧ£®ËùÒÔ£¬ÕâÖÖµª·ÊÒ²²»ÄÜÓëÊìʯ»ÒÒ»ÆðÊ©Óã®·´Ó¦µÄ·½³ÌʽÊÇ£º£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü£®
¹Ê´ðΪ£º£¨1£©Î¬ÉúËØºÍÌÇÀࣻ£¨2£©£¨NH4£©2SO4£»£¨3£©£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü£®
£¨2£©µ¼ÖÂÍÁÈÀËữºÍ°å½áµÄµª·ÊÊÇÁòËáï§£¬»¯Ñ§Ê½ÊÇ£ºNH4£©2SO4£»
£¨3£©ÓÉÓÚÁòËáï§ÄÜÓëÊìʯ»ÒÄÜ·´Ó¦·Å³ö°±Æø£¬½µµÍ·ÊЧ£®ËùÒÔ£¬ÕâÖÖµª·ÊÒ²²»ÄÜÓëÊìʯ»ÒÒ»ÆðÊ©Óã®·´Ó¦µÄ·½³ÌʽÊÇ£º£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü£®
¹Ê´ðΪ£º£¨1£©Î¬ÉúËØºÍÌÇÀࣻ£¨2£©£¨NH4£©2SO4£»£¨3£©£¨NH4£©2SO4+Ca£¨OH£©2=CaSO4+2H2O+2NH3¡ü£®
µãÆÀ£º»¯Ñ§À´Ô´ÓÚÉú²ú¡¢Éú»î£¬ÓÖ·þÎñÓÚÉú²ú¡¢Éú»î£¬Òò´ËÓëÉú²ú¡¢Éú»îʵ¼ùÏà¹ØµÄ»¯Ñ§ÖªÊ¶£¬ÔÚÖп¼ÖгöÏֵįµ¶ÈºÜ¸ß£¬Ñ§Ï°¹ý³ÌÖÐÒªÒýÆðÖØÊÓ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿