ÌâÄ¿ÄÚÈÝ

17£®ÈçͼËùʾװÖÃÖеÄÏÖÏóÊÇʵÑé¹ý³ÌÖгÊÏÖµÄʵÑéÏÖÏó£¬Çë»Ø´ðÏà¹ØÎÊÌ⣮
£¨1£©¶à¿×Í­ÖÆ¸ô°åÉÏÃæÈô·ÅÖÃʯ»Òʯ£¬´ò¿ªÖ¹Ë®¼ÐM£¬È¡ÏÂ×ó²àµÄÏð½ºÈû£¬ÏòUÐ͹ÜÄÚ¼ÓÈëÏ¡ÑÎËᣬUÐ͹ÜÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl=CaCl2+H2O+CO2¡ü£¬Ò»¶Îʱ¼äºó£¬¹Ø±ÕMºó£¬³ÊÏÖÈçͼËùʾµÄÏÖÏóµÄÔ­ÒòÊǹرÕMºó£¬Éú³ÉµÄ¶þÑõ»¯Ì¼Ê¹µÄѹǿÔö´ó£¬½«ÒºÌåÓë¹ÌÌå·ÖÀ룮
£¨2£©¶à¿×Í­ÖÆ¸ô°åÉÏÃæÈô·ÅÖð×Á×£¬UÐ͹ÜÄÚ×¢Èë80¡æµÄÈÈË®£¬UÐ͹ÜÓÒ¹ÜÄÚÈÈË®½þû°×Á×£¬´ËʱµÄʵÑéÏÖÏóÊǰ×Á×ÈÛ»¯£¬µ«²»È¼ÉÕ£¬´ò¿ªÖ¹Ë®¼ÐM£¬¾­M´¦ÏòUÐ͹ÜÄÚ²»¶Ï³äÈëÑõÆøºóµÄÏÖÏóÊǰ×Á×ȼÉÕ£¬´ËʵÑé¿ÉÖ¤Ã÷ȼÉÕÌõ¼þÖ®Ò»ÊÇÓëÑõÆø½Ó´¥£®

·ÖÎö £¨1£©Ì¼Ëá¸ÆÓëÑÎËá·´Ó¦Éú³ÉÁ˲âÑõ»¯Ì¼ÆøÌ壬¹Ø±ÕMºó£¬ÓÒ²à¹ÝÄÚѹǿÔö´ó£¬¾Ý´Ë·ÖÎö»Ø´ð£»
£¨2£©¸ù¾ÝȼÉÕµÄÌõ¼þ·ÖÎöÅжϣ®

½â´ð ½â£º£¨1£©¶à¿×Í­ÖÆ¸ô°åÉÏÃæÈô·ÅÖÃʯ»Òʯ£¬´ò¿ªÖ¹Ë®¼ÐM£¬È¡ÏÂ×ó²àµÄÏð½ºÈû£¬ÏòUÐ͹ÜÄÚ¼ÓÈëÏ¡ÑÎËᣬUÐ͹ÜÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl=CaCl2+H2O+CO2¡ü£¬Ò»¶Îʱ¼äºó£¬¹Ø±ÕMºó£¬³ÊÏÖÈçͼËùʾµÄÏÖÏóµÄÔ­ÒòÊǹرÕMºó£¬Éú³ÉµÄ¶þÑõ»¯Ì¼Ê¹µÄѹǿÔö´ó£¬½«ÒºÌåÓë¹ÌÌå·ÖÀ룮
£¨2£©¶à¿×Í­ÖÆ¸ô°åÉÏÃæÈô·ÅÖð×Á×£¬UÐ͹ÜÄÚ×¢Èë80¡æµÄÈÈË®£¬UÐ͹ÜÓÒ¹ÜÄÚÈÈË®½þû°×Á×£¬´ËʱµÄʵÑéÏÖÏóÊǰ×Á×ÈÛ»¯£¬µ«²»È¼ÉÕ£¬´ò¿ªÖ¹Ë®¼ÐM£¬¾­M´¦ÏòUÐ͹ÜÄÚ²»¶Ï³äÈëÑõÆøºóµÄÏÖÏóÊǰ×Á×ȼÉÕ£¬´ËʵÑé¿ÉÖ¤Ã÷ȼÉÕÌõ¼þÖ®Ò»ÊÇÓëÑõÆø½Ó´¥£®
¹Ê´ðΪ£º£¨1£©CaCO3+2HCl=CaCl2+H2O+CO2¡ü£¬¹Ø±ÕMºó£¬Éú³ÉµÄ¶þÑõ»¯Ì¼Ê¹ÓÒ²à¹ÝÄÚµÄѹǿÔö´ó£¬½«ÒºÌåÓë¹ÌÌå·ÖÀ룮
£¨2£©°×Á×ÈÛ»¯£¬µ«²»È¼ÉÕ   °×Á×ȼÉÕ  ÓëÑõÆø½Ó´¥£®

µãÆÀ ±¾ÌâµÄÄѶȲ»´ó£¬Á˽â¶þÑõ»¯Ì¼µÄʵÑéÖÆÈ¡·½·¨ºÍȼÉÕµÄÌõ¼þÊǽâ´ð±¾ÌâµÄ»ù´¡ÖªÊ¶£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø