Question

13g锌与100g某硫酸溶液恰好完全反应．试计算这种硫酸溶液中溶质的质量分数．

Answer 1

设100g硫酸溶液中所含H₂SO₄的质量是x
Zn+H₂SO₄═ZnSO₄+H₂↑
65   98
13g   x

65

13g

=

98

x

x=19.6g
H₂SO₄%=

19.6g

100g

×100%=19.6%
答：这种硫酸溶液中溶质的质量分数是19.6%．