ÌâÄ¿ÄÚÈÝ

СÃ÷¼ÒÂòÁËÒ»´ü̼ËáÇâï§£¨NH4HCO3£©»¯·Ê£¬²»É÷Ëð»µÁËʹÓÃ˵Ã÷£®ÎªÁËÕýȷʹÓøû¯·Ê£¬Ð¡Ã÷²éÔÄÏà¹Ø×ÊÁÏ£¬Á˽⵽̼ËáÇâï§µÄÓйØÐÔÖÊ£ºÒ×ÈÜÓÚË®£¬Êܳ±Ê±ÔÚ³£ÎÂÏÂÒ׷ֽ⣬ζÈÔ½¸ß·Ö½âÔ½¿ì£¬Óö¼îʱ·Å³ö°±Æø£¨NH3£©£®
£¨1£©Ì¼ËáÇâï§ÊôÓÚ³£¼û»¯·ÊÖеÄ______·Ê£»
£¨2£©Ð¡Ã÷Äâ³ö¸Ã»¯·ÊÔÚÖü´æºÍʹÓÃʱµÄ×¢ÒâÊÂÏîÈçÏ£¬ÄãÈÏΪÕýÈ·µÄÊÇ______£®
¢ÙÖü´æ¡¢ÔËÊäʱҪÃÜ·â        ¢ÚÖü´æ¡¢ÔËÊäʱ²»ÒªÊܳ±»òÆØÉ¹
¢ÛÊ©ÓúóÒª¸ÇÍÁ»òÁ¢¼´¹à¸È    ¢ÜÓë¼îÐÔ·ÊÁϲÝľ»Ò»ìºÏʹÓã®
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©¸ù¾Ý̼ËáÇâï§£¨NH4HCO3£©Öк¬Óеª¡¢Áס¢¼ØÖеĵªÔªËØ·ÖÎö£»
£¨2£©¸ù¾ÝÌâÄ¿ÌṩµÄÐÅÏ¢£ºÒ×ÈÜÓÚË®£¬Êܳ±Ê±ÔÚ³£ÎÂÏÂÒ׷ֽ⣬ζÈÔ½¸ß·Ö½âÔ½¿ì£¬Óö¼îʱ·Å³ö°±Æø£¨NH3£©£®
½â´ð£º½â£º£¨1£©Ì¼ËáÇâï§£¨NH4HCO3£©Öк¬Óеª¡¢Áס¢¼ØÖеĵªÔªËØ£¬ÊôÓÚµª·Ê£®
¹Ê´ð°¸Îª£ºµª£®
£¨2£©Ì¼ËáÇâï§Ò×ÈÜÓÚË®£¬Êܳ±Ê±ÔÚ³£ÎÂÏÂÒ׷ֽ⣬ζÈÔ½¸ß·Ö½âÔ½¿ì£¬Óö¼îʱ·Å³ö°±Æø£¨NH3£©£¬ËùÒÔÖü´æ¡¢ÔËÊäʱҪÃܷ⣬Öü´æ¡¢ÔËÊäʱ²»ÒªÊܳ±»òÆØÉ¹£¬Ê©ÓúóÒª¸ÇÍÁ»òÁ¢¼´¹à¸È£¬²»µÃÓë¼îÐÔ·ÊÁϲÝľ»Ò»ìºÏʹÓã®
¹Ê´ð°¸Îª£º¢Ù¢Ú¢Û£®
µãÆÀ£º±¾Ì⿼²é»¯·ÊµÄÖÖÀàºÍ¸ù¾ÝÐÅÏ¢½âÌ⣬ͬѧÃÇÒªÔÚÁ˽â»ù±¾ÖªÊ¶µÄ»ù´¡ÉÏ£¬×ÐϸÔĶÁÌâÄ¿£¬²¢ÏàПù¾ÝËùѧ֪ʶһ¶¨Äܹ»½âºÃÌâÄ¿£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
19¡¢Ð¡Ã÷¼Ò¹ºÂòÁËһƿ°×´×£¬±êÇ©ÉÏ×¢Ã÷´×ËáµÄÖÊÁ¿·ÖÊý¡Ý5%£®Ð¡Ã÷Ï룺ÕâÆ¿°×´×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿ÇëÄãÓÃÓйØËá¼îµÄ֪ʶ£¬¶¨Á¿²â¶¨°×´×Öд×ËáµÄº¬Á¿£®
Ò»¡¢¡¾ÊµÑéÔ­Àí¡¿£º£¨1£©ÓÃÒÑ֪Ũ¶ÈµÄÇâÑõ»¯ÄÆÈÜÒººÍ´×Ëá·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
CH3COOH+NaOH=CH3COONa+H2O
£¨2£©ÔÚ»ìºÏÈÜÒºÖУ¬µ±´×ËáºÍÇâÑõ»¯ÄÆÍêÈ«ÖкÍʱ£¬ÔÙÔö¼Ó1µÎÇâÑõ»¯ÄÆÈÜÒº£¬ÈÜÒº¾Í³Ê¼îÐÔ£¬¶ø1µÎÇâÑõ»¯ÄÆÈÜҺԼΪ0.05 mL£¬¶Ô²â¶¨½á¹ûµÄÓ°ÏìºÜС£¬¿ÉºöÂÔ²»¼Æ£®
¶þ¡¢¡¾ÊµÑé²½Öè¡¿£º£¨1£©ÓÃ
Á¿Í²
È¡12.0 mL°×´×£¨ÃܶȽüËÆÎª1.0g/mL£©£¬µ¹ÈëÉÕ±­ÖУ¬¼ÓÈë20 mLÕôÁóˮϡÊÍ£¬ÔÙµÎÈ뼸µÎ·Ó̪ÊÔÒº£®
£¨2£©Á¿È¡45.0 mLÈÜÖÊÖÊÁ¿·ÖÊýΪ1.0%µÄÇâÑõ»¯ÄÆÈÜÒº£¨ÃܶȽüËÆÎª1.0 g/mL£©£¬ÓýºÍ·µÎ¹ÜÈ¡¸ÃÇâÑõ»¯ÄÆÈÜÒº£¬ÖðµÎµØµÎ¼Óµ½Ï¡ÊͺóµÄ°×´×ÖУ¬Í¬Ê±²»¶ÏµØ½Á°èÉÕ±­ÖеÄÈÜÒº£®µÎÖÁÇ¡ºÃÍêÈ«·´Ó¦£¬Ê£ÓàÇâÑõ»¯ÄÆÈÜÒº5.0 mL£®
Èý¡¢¡¾½»Á÷·´Ë¼¡¿£º£¨1£©ÔÚʵÑé²½Ö裺¢ÙÖУ¬¼ÓÊÊÁ¿Ë®Ï¡ÊͰ״ף¬¶ÔʵÑé½á¹ûÓÐÎÞÓ°Ï죿Ϊʲô£¿
£¨2£©ÔÚʵÑé²½Öè2 ¢ÚÖУ¬Ð¡Ã÷ÈçºÎÈ·¶¨´×ËáºÍÇâÑõ»¯ÄÆÒÑÍêÈ«Öкͣ¿
ËÄ¡¢¡¾Êý¾Ý´¦Àí¡¿£º¸ù¾ÝʵÑéÊý¾Ý£¬Í¨¹ý¼ÆËãÅжϰ״×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿£¨¿ÉÄÜÓõ½µÄÏà¶ÔÔ­×ÓÖÊÁ¿£ºH-1£¬C-12£¬O-16£¬Na-23£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø