ÌâÄ¿ÄÚÈÝ
30.ij»¯Ñ§»î¶¯Ð¡×éÓûÓô¿¼îÖÆÈ¡Éռ×öÁËÈçÏÂʵÑ飺ÏÖÈ¡´¿¼îÑùÆ·£¨¼ÙÉèÔÓÖʲ»ÈÜÓÚË®£¬Ò²²»ÓëÆäËûÎïÖÊ·´Ó¦£©£¬ÏòÆäÖмÓÈë34.1gˮʹÆäÍêÈ«Èܽ⣬ȻºóÔÙ¼ÓÈë100gµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ17.1%µÄÇâÑõ»¯±µÈÜÒº£¬ÖÁÇ¡ºÃÍêÈ«·´Ó¦£¬¹ýÂ˵õ½29.1gÂËÔüºÍÒ»ÖÖ²»±¥ºÍÈÜÒº¡£Çë»Ø´ðÎÊÌ⣺
£¨1£©ÉÏÊöʵÑé²½ÖèÖУ¬ÇëÖ¸³ö²Ù×÷ÖеĴíÎó ;
£¨2£©Çëд³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ ;
£¨3£©Áгö²Î¼Ó·´Ó¦¹ÌÌåÎïÖÊÖÊÁ¿£¨x£©µÄ±ÈÀýʽ £»
£¨4£©Çó´¿¼îÑùÆ·µÄ´¿¶ÈΪ £»
£¨5£©·´Ó¦ºóËùµÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ £»
£¨6£©ÏÖ½«·´Ó¦ºóËùµÃÈÜҺŨËõ³É10%µÄÈÜÒºÒÔ±¸Óã¨Å¨ËõʱûÓо§ÌåÎö³ö£©£¬ÔòÐèÕô·¢µôµÄË®µÄÖÊÁ¿Îª ¡£
(1)¹ýÂËʱûÓÐÓò£Á§°ôÒýÁ÷£¬Â©¶·×îµ×¶ËûÓнô¿¿ÉÕ±ÄÚ±Ú
(2)Ba£¨OH£©2+Na2CO3=2NaOH+BaCO3¡ý
(3)106/171=x/17.1g
(4)53%
(5)6.4%
£¨6£©45g ½âÎö:
ÂÔ
(2)Ba£¨OH£©2+Na2CO3=2NaOH+BaCO3¡ý
(3)106/171=x/17.1g
(4)53%
(5)6.4%
£¨6£©45g ½âÎö:
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿