ÌâÄ¿ÄÚÈÝ

4£®¸ù¾ÝÄãËùѧϰµÄ»¯Ñ§ÖªÊ¶£¬Íê³ÉÏÂÁÐÌî¿Õ£¬ÄÜд³ö»¯Ñ§·½³ÌʽµÄд³ö·½³Ìʽ£®
£¨1£©¹¤ÒµÁ¶Ìúʱ£¬ÎªÁ˰ÑÌú¿óʯÖеĶþÑõ»¯¹èת»¯ÎªÂ¯Ôü£¬ÍùÍù»áÏò¸ß¯ÖÐÌí¼Óʯ»Òʯ£»
£¨2£©Óû¯Ñ§·½³Ìʽ±íʾÂÁ¾ßÓÐÓÅÁ¼µÄ¿¹¸¯Ê´ÐÔÄܵÄÔ­ÒòÊÇ4Al+3O2=2Al2O3£»
£¨3£©Ä³±ý¸É°ü×°´üÖÐÓÃ×÷¸ÉÔï¼ÁµÄÊÇÉúʯ»Ò£¬Ô­ÀíCaO+H2O¨TCa£¨OH£©2£»£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
£¨4£©ÌìÈ»ÆøÊÇÒ»ÖÖÇå½àÄÜÔ´£¬Ð´³öÆäÔÚ¿ÕÆøÖгä·ÖȼÉյĻ¯Ñ§·½³ÌʽCH4+2O2 $\frac{\underline{\;µãȼ\;}}{\;}$CO2+2H2O£»
£¨5£©ÀûÓöþÑõ»¯Ì¼ºÍµªÆøÔÚ´ß»¯¼Á¸ßθßѹϺϳÉÄòËØCO£¨NH2£©2£¬¸Ã·´Ó¦Êǹ̶¨ºÍÀûÓÃCO2µÄ³É¹¦·¶Àý£¬Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+2NH3$\frac{\underline{\;\;´ß»¯¼Á\;\;}}{¸ßθßѹ}$CO£¨NH2£©2+H2O£®

·ÖÎö £¨1£©¸ù¾ÝÁ¶ÌúµÄÔ­ÁϺÍ×÷ÓýøÐзÖÎö½â´ð£»
£¨2£©¸ù¾ÝÂÁµ¥Öʼ«Ò׺ÍÑõÆøÐγÉÖÂÃÜÑõ»¯Ä¤Êéд»¯Ñ§·½³Ìʽ£»
£¨3£©Éúʯ»Ò¼«Ò׺ÍË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬ÊÇʹÓ÷½±ãµÄ¹ÌÌå¸ÉÔï¼Á£»
£¨4£©ÌìÈ»ÆøµÄÖ÷Òª³É·ÖΪ¼×Í飬ÔÚ¿ÕÆøÖгä·ÖȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®£»
£¨5£©ÐÅÏ¢ÐÍ·½³ÌʽµÄÊéд£¬ÔÚÉú³ÉÄòËØµÄͬʱ£¬Ã¿¸ö¶þÑõ»¯Ì¼ÉÙÁËÒ»¸öÑõÔ­×Ó£¬¶øÃ¿¸ö°±·Ö×ÓÉÙÁË1¸öÇâÔ­×Ó£¬¶ø°±·Ö×Ó¸ù¾ÝÄòËØµÄ»¯Ñ§Ê½Ó¦¸ÃÓÐÁ½¸ö£¬ËùÒÔÕâÑùÒ²¾ÍÊÇÒ»¸öË®·Ö×Ó£®¸ù¾ÝÕâ¸ö·ÖÎö½á¹ûÊéд»¯Ñ§·½³Ìʽ£®

½â´ð ½â£º£¨1£©¹¤ÒµÁ¶Ìúʱ£¬Ê¯»ÒʯÊÇÔìÔü²ÄÁÏ£¬Ö÷ÒªÊǺͶþÑõ»¯¹è·´Ó¦Éú³É¯Ôü£®
£¨2£©ÂÁ¾ß¾ßÓÐÓÅÁ¼µÄ¿¹¸¯Ê´ÐÔÄÜÔ´ÓÚÕâÖÖ½ðÊô»îÆÃ£¬ºÜÈÝÒ×ºÍ¿ÕÆøÖеÄÑõÆø½áºÏÉú³ÉÑõ»¯ÂÁ£¬×îÓÅÁ¼µÄÊÇÕâÖÖÑõ»¯Ä¤ºÜÖÂÃÜ£¬´Ó¶ø×èÖ¹ÄÚ²¿µÄÂÁºÍÑõÆøµÄ½Ó´¥£¬Ìá¸ßÁË¿¹¸¯Ê´ÐÔ£®¶ÔÓ¦µÄ»¯Ñ§·½³ÌʽΪ£º4Al+3O2=2Al2O3£®
£¨3£©Éúʯ»Ò¼«Ò׺ÍË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬ÊÇ×î¼ÑµÄ¹ÌÌå¸ÉÔï¼Á£¬³£ÓÃÓÚ¸÷ÖÖ¹ÌÌåÐÍÎïÖʰü×°£¬ÒòΪ¾ßÓÐÒ»¶¨¸¯Ê´ÐÔ£¬Òò´ËÑÏ·ÀÓ¤Ó×¶ùÎó·þ£®¶ÔÓ¦µÄ»¯Ñ§·½³ÌʽΪ CaO+H2O¨TCa£¨OH£©2£®
£¨4£©ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬ÆäÔÚ¿ÕÆøÖгä·ÖȼÉÕÊÇÉú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬¶ÔÓ¦µÄ»¯Ñ§·½³Ìʽ CH4+2O2 $\frac{\underline{\;µãȼ\;}}{\;}$CO2+2H2O£®
£¨5£©ÀíÀûÓÃCO2ºÍNH3ÔÚ´ß»¯¼Á¸ßθßѹϺϳÉÄòËØCO£¨NH2£©2£¬ÔÚÉú³ÉÄòËØCO£¨NH2£©2µÄͬʱ£¬Ã¿¸ö¶þÑõ»¯Ì¼ÉÙÁËÒ»¸öÑõÔ­×Ó£¬¶øÃ¿¸ö°±·Ö×ÓÉÙÁË1¸öÇâÔ­×Ó£¬¶ø°±·Ö×Ó¸ù¾ÝÄòËØµÄ»¯Ñ§Ê½Ó¦¸ÃÓÐÁ½¸ö£¬ËùÒÔÕâÑùÒ²¾ÍÊÇÒ»¸öË®·Ö×Ó£® Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+2NH3$\frac{\underline{\;\;´ß»¯¼Á\;\;}}{¸ßθßѹ}$CO£¨NH2£©2+H2O£®
¹Ê´ð°¸Îª£º£¨1£©Ê¯»Òʯ£»
£¨2£©4Al+3O2=2Al2O3£»
£¨3£©CaO+H2O¨TCa£¨OH£©2£»
£¨4£©CH4+2O2 $\frac{\underline{\;µãȼ\;}}{\;}$CO2+2H2O£»
£¨5£©CO2+2NH3$\frac{\underline{\;\;´ß»¯¼Á\;\;}}{¸ßθßѹ}$CO£¨NH2£©2+H2O£®

µãÆÀ ÑϸñÌâÄ¿ÏÞÖÆÌõ¼þÊéд¶ÔÓ¦»¯Ñ§·½³Ìʽ£¬Í¬Ê±×¢ÒâÐÅÏ¢ÐÍ·½³ÌʽµÄÊéд¸üÒª´Ó¸ø³öµÄÐÅÏ¢ÖÐÕÒµ½ËùÓÐÒªËØ£¬±ÜÃâÒÅ©£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
14£®¡°¼ÒʹúÊÂÌìÏÂÊ£¬ÊÂʹØÐÄ¡±£®×÷ΪÐÂʱ´úµÄÖÐѧÉú£¬ÎÒÃDz»½öҪѧϰÎÄ»¯ÖªÊ¶£¬¶øÇÒÒª¹Ø×¢Éç»á£¬¹Ø×¢Éú»î£®
£¨1£©2013Äê4ÔÂ20ÈÕ8µã02·ÖËÄ´¨Ê¡ÑŰ²ÊÐÂ«É½ÏØ·¢Éú7.0¼¶µØÕ𣮵ØÕð·¢Éúºó£¬È«¹úÈËÃñ¿¹Õð¾ÈÔÖ£¬ÖÚÖ¾³É³Ç£¬ÕÃÏÔÁËÖлªÃñ×å¾Þ´óµÄÄý¾ÛÁ¦£®
¢Ù¾ÈÔÖÐèÒª´óÁ¿µÄÏû¶¾¼Á£¬ÎÒ¹úÑÐÖÆ³ö±ÈƯ°×·Û¸ü¸ßЧµÄÒûÓÃË®Ïû¶¾¼Á¡°ClO2¡±£¬Æä·´Ó¦µÄ΢¹Û¹ý³ÌÈçͼ1Ëùʾ£º

£¨ÆäÖР±íʾÂÈÔ­×Ó£¬¡ñ±íÊ¾ÄÆÔ­×Ó£¬ ±íʾÑõÔ­×Ó£©
ÊԻشð£ºClO2ÖÐÂȵϝºÏ¼ÛΪ+4£®
¸ù¾Ý·´Ó¦µÄ΢¹Û¹ý³Ìͼд³ö·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCl2+2NaClO2=2ClO2+2NaCl£®
¢Ú¹ú¼ÒÒ©¼à¾Ö¹«²¼µÄ¿¹Õð¾ÈÔÖ¼±ÐèҩеĿ¼ÖаüÀ¨£ºÒ»´ÎÐÔ·À»¤·þ¡¢»îÐÔÌ¿·À»¤¿ÚÕÖ¡¢¹Ç¿ÆÄÚÍâ¹Ì¶¨²ÄÁϵȣ®ÆäÖзÀ»¤¿ÚÕÖÖ÷ÒªÊÇÀûÓûîÐÔÌ¿µÄÎü¸½ÐÔ£®
¢ÛµØÕð·¢Éúºó£¬È«¹ú¸÷µØÎªÔÖÇø½ô¼±Ìṩ°üÀ¨·½±ãÃæÔÚÄڵĸ÷ÖÖ¾ÈÔÖÎïÆ·£®¾ÝÈç±í»Ø´ð£º
·½±ãÃæÓªÑø³É·Ö±í£¨Ã¿100gÖк¬Á¿£©
ÌÇÀà
£¨g£©
Ö¬·¾
£¨g£©
µ°°×ÖÊ
£¨g£©
Ë®·Ö
£¨g£©
ÄÆ
£¨mg£©
¼Ø
£¨mg£©
Á×
£¨mg£©
¸Æ
£¨mg£©
άÉúËØC
£¨mg£©
ÆäËû
61.621.19.53.6114413480250¡­
·½±ãÃæËùº¬µÄÓªÑøËØÖ÷ÒªÓе°°×ÖÊ¡¢ÌÇÀà¡¢ÓÍÖ¬¡¢ÎÞ»úÑκÍË®£®
£¨2£©Óлú¸ß·Ö×Ó²ÄÁÏ¡¢½ðÊô²ÄÁϺÍÎÞ»ú·Ç½ðÊô²ÄÁÏÊÇÈËÀàʹÓõÄÈý´óÀà»ù´¡²ÄÁÏ£¬ËüÃÇÒÔ¸÷×ÔµÄÌØµãÂú×ã×ÅÈËÀà¶à·½ÃæµÄÐèÒª£®
¢Ù½ðÊô²ÄÁÏÖУ¬ÓÐÒ»ÀàÖüÇâºÏ½ðÄܹ»½áºÏÇâÆøÐγɽðÊô»¯ºÏÎ²¢ÔÚÒ»¶¨Ìõ¼þÏ·ֽâÊͷųöÇâÆø£¬¸ÃÖüÔËÔ­ÀíÊôÓÚ»¯Ñ§±ä»¯£¨Ñ¡Ìî¡°ÎïÀí¡±»ò¡°»¯Ñ§¡±£©£®
¢ÚÎÞ»ú·Ç½ðÊô²ÄÁÏÖУ¬ÓÃÓÚµç×Ó¹¤ÒµµÄ¸ß´¿Ì¼Ëá¸ÆºÍ¸ß´¿Ñõ»¯¸ÆÉú²úÁ÷³ÌÈçͼ2Ëùʾ
ʵÑéÊÒ³£²ÉÓùýÂ˲Ù×÷½øÐгÁµí·ÖÀ룬Éú²ú¸ß´¿Ì¼Ëá¸ÆÊ±£¬Ñ¡Ôñ¡°220¡æºãθÉÔ£¬¶ø²»Ñ¡Ôñ¡°¸ßΡ±Ìõ¼þÏÂÍê³É´Ë²Ù×÷µÄÔ­ÒòÊÇCaCO3$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CaO+CO2¡ü£¨Óû¯Ñ§·½³Ìʽ˵Ã÷£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø