ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÔÚÈÕ³£Éú»îÖУ¬ÖÆ×÷ÂøÍ·Ê±³£¼ÓÈëÅÝ´ò·Û£¬ÔÚÖÆ×÷¹ý³ÌÖÐÓÉÓÚ²úÉú¶þÑõ»¯Ì¼ÆøÌå£¬Ê¹ÂøÍ·±äµÃËÉÈí¿É¿Ú¡£Ä³Ð¡×éͬѧ¶ÔÅÝ´ò·ÛµÄ·¢ÃæÔ­Àí²úÉúÐËȤ£¬½øÐÐÁËÒÔÏÂʵÑé̽¾¿¡£

£¨²éÔÄ×ÊÁÏ£©ÅÝ´ò·ÛÊÇÒ»ÖÖ¸´ºÏÅòËɼÁ£¬ÓÖ³ÆÎª·¢ÅÝ·Û£¬¿É×÷Ϊ¿ìËÙ·¢Ãæ¼ÁÓÃÓÚÖÆ×÷ÃæÊ³¡£Ä³ÖÖÅÝ´ò·ÛµÄÖ÷Òª³É·ÖÊÇСËÕ´ò·ÛºÍ¾ÆÊ¯ËáÇâ¼Ø¡£

£¨Ìá³öÎÊÌ⣩ÅÝ´ò·ÛΪʲô»á²úÉú¶þÑõ»¯Ì¼ÆøÌ壿

£¨²ÂÏëÓë¼ÙÉ裩

²ÂÏë1£ºÐ¡ËÕ´òÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼ÆøÌå

²ÂÏë2£º¾ÆÊ¯ËáÇâ¼ØÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼ÆøÌå

²ÂÏë3£ºÐ¡ËÕ´òºÍ¾ÆÊ¯ËáÇâ¼ØÔÚÈÜÒºÖз¢Éú·´Ó¦£¬²úÉú¶þÑõ»¯Ì¼ÆøÌå

ʵÑé

ʵÑé²Ù×÷

ʵÑéÏÖÏó

1

ÔÚ×°ÖÃ1µÄaÊÔ¹ÜÖзÅÈëСËÕ´ò£¬¼ÓÈÈ

aÊԹܿÚÄÚ±ÚÓÐÎÞɫҺµÎ£¬

bÊÔ¹ÜÖÐʯ»ÒË®±ä»ë×Ç¡£

2

ÔÚ×°ÖÃ1µÄaÊÔ¹ÜÖзÅÈë¾ÆÊ¯ËáÇâ¼Ø£¬¼ÓÈÈ

aÊԹܿÚÄÚ±ÚÓÐÎÞɫҺµÎ£¬

bÊÔ¹ÜÖÐʯ»ÒË®²»±ä»ë×Ç

3

ÔÚ×°ÖÃ2µÄcÊÔ¹ÜÖзÅÈëСËÕ´òºÍ¾ÆÊ¯ËáÇâ¼ØµÄ»ìºÏÎµÎ¼Ó________¡£

,dÊÔ¹ÜÖÐʯ»ÒË®±ä»ë×Ç

£¨½øÐÐʵÑ飩ÀûÓÃÒÔÏÂʵÑé×°ÖýøÐÐ̽¾¿

£¨½âÊÍÓë½áÂÛ£©

£¨1£©Ë׳ÆÐ¡ËÕ´òµÄÎïÖÊÊÇ_______________¡£

£¨2£©ÊµÑé1ÖУ¬bÊÔ¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________¡£

£¨3£©ÊµÑé2µÄÏÖÏó±íÃ÷£¬²ÂÏë2_________£¨Ìî¡°³ÉÁ¢¡±»ò¡°²»³ÉÁ¢¡±£©¡£

£¨4£©ÊµÑé3µÄ²Ù×÷£º ÔÚ×°ÖÃ2µÄcÊÔ¹ÜÖзÅÈëСËÕ´òºÍ¾ÆÊ¯ËáÇâ¼ØµÄ»ìºÏÎµÎ¼Ó______________£¬ÊµÑéÏÖÏóΪ_______________ £¬Ê¯»ÒË®±ä»ë×Ç¡£²ÂÏë3³ÉÁ¢¡£

£¨·´Ë¼ÓëÆÀ¼Û£©

£¨5£©Í¨¹ýÒÔÉÏʵÑé̽¾¿£¬Ð¡×éͬѧÓÖ²éÔĵ½Ì¼ËáÇâÄÆ·Ö½âµÄ·´Ó¦Îª£º2NaHCO3Na2CO3 + H2O + CO2¡ü£¬ ¸ù¾ÝÒÔÉÏʵÑé½áÂÛºÍËùѧ֪ʶ£¬Ð¡×éͬѧ¶Ô̽¾¿ÎÊÌâÓÖÌá³öÁ˵Ú4¸ö²ÂÏ룬²¢ÔÚÒÔÉÏʵÑéµÄ»ù´¡ÉÏ£¬ÀûÓÃ×°ÖÃ2Íê³ÉʵÑéÑéÖ¤£¬ÆäʵÑé·½°¸Îª_______________________¡£

£¨6£©Í¨¹ýÒÔÉÏʵÑé̽¾¿£¬ÏÂÁйØÓÚÅÝ´ò·ÛµÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ_______¡£

A ÅÝ´ò·Û±£´æÊ±Òª×¢Òâ·À³±

B ÕôÂøÍ·Ê±£¬ÏȽ«ÅÝ´ò·ÛÈÜÓÚË®£¬ÔÙÓôËÈÜÒºÓëÃæ·ÛºÍ³ÉÃæÍÅ

C Óô¿¼îÌæ´úСËÕ´òÖÆ³ÉµÄÅÝ´ò·ÛÕôÂøÍ·Ê±£¬Ò²ÄÜÆðµ½ÅòËɵÄЧ¹û

D ÔÚÓÃÅÝ´ò·ÛÕôÂøÍ·Ê±£¬ÔÚ¼ÓË®ÈàÃæ¹ý³ÌÓëÕôµÄ¹ý³ÌÖоùÄÜÆðµ½·¢Ãæ×÷ÓÃ

¡¾´ð°¸¡¿³ÎÇåʯ»ÒË® ̼ËáÇâÄÆ £¨NaHCO3£© CO2+ Ca(OH)2= CaCO3¡ý+ H2O ²»³ÉÁ¢ Ë® cÊÔ¹ÜÖÐÓÐÆøÅݲúÉú ´ýʵÑé1³ä·Ö·´Ó¦ºó£¬È¡ÊÔ¹ÜaÖÐÊ£Óà¹ÌÌåºÍ¾ÆÊ¯ËáÇâ¼Ø£¬·ÅÈë×°ÖÃ2µÄÊÔ¹ÜcÖУ¬µÎ¼ÓÒ»¶¨Á¿Ë®ºó£¬ÈôÊÔ¹ÜcÖÐÓÐÆøÅݲúÉú£¬ÊÔ¹ÜdÖеijÎÇåʯ»ÒË®±ä»ë×Ç£¬Ôò²ÂÏë4ÕýÈ·¡£ ACD

¡¾½âÎö¡¿

aÊÔ¹ÜÖÐʯ»ÒË®±ä»ë×Ç£¬ËµÃ÷ÊǶþÕß·´Ó¦µÄ½á¹û²úÉú¶þÑõ»¯Ì¼£¬Òò´ËÏò»ìºÏÎïÖмÓË®ÈܽⷴӦ²úÉú¶þÑõ»¯Ì¼£»

[½âÊÍÓë½áÂÛ]

£¨1£©Ë׳ÆÐ¡ËÕ´òµÄÎïÖÊÊÇ̼ËáÇâÄÆ£¬»¯Ñ§Ê½ÎªNaHCO3£»

£¨2£©ÊµÑé1ÖУ¬aÊÔ¹ÜÖз¢Éú·´Ó¦ÎªÌ¼ËáÇâÄÆÔÚ¼ÓÈÈÌõ¼þÏ·ֽâÉú³É¶þÑõ»¯Ì¼¡¢Ì¼ËáÄÆ¡¢Ë®£¬bÊÔ¹ÜÖз´Ó¦ÎªÇâÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍË®£¬·´Ó¦·½³ÌʽΪ£ºCO2+ Ca(OH)2= CaCO3¡ý+ H2O£»

£¨3£©¸ù¾ÝʵÑé·½°¸¼°ÊµÑéÏÖÏó£ºÔÚ×°ÖÃ1µÄaÊÔ¹ÜÖзÅÈë¾ÆÊ¯ËáÇâ¼Ø£¬Ê¯»ÒˮûÓбä»ë×Ç£¬ËµÃ÷¼ÓÈȾÆÊ¯ËáÇâ¼Ø²»ÄܲúÉú¶þÑõ»¯Ì¼£¬Òò´Ë²ÂÏë2²»ÕýÈ·£»

£¨4£©ÊµÑé3µÄ²Ù×÷£º ÔÚ×°ÖÃ2µÄcÊÔ¹ÜÖзÅÈëСËÕ´òºÍ¾ÆÊ¯ËáÇâ¼ØµÄ»ìºÏÎµÎ¼ÓË®£¬ÊµÑéÏÖÏóΪÓÐÆøÅݲúÉú£¬Ê¯»ÒË®±ä»ë×Ç¡£²ÂÏë3³ÉÁ¢¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ÕäÖé·ÛÊÇÓÉÕäÖé¼Ó¹¤ÖƳɵİ×É«·ÛÄ©£¬Ö÷Òª³É·ÖÊÇ̼Ëá¸Æ£¬ÊÇÖØÒªµÄ»¯×±Æ·Ô­ÁÏ£¬Êг¡ÉϳöÏֵļÙÕäÖé·ÛÍâ¹ÛÉÏÓëÕæÕäÖé·Û²î²»¶à£¬ÈâÑÛÎÞ·¨±æ±ðËüÃÇ¡£

£¨Ìá³öÎÊÌ⣩¼ÙÕäÖé·ÛµÄÖ÷Òª³É·ÖÊÇʲô£¿Õæ¼ÙÕäÖé·ÛµÄ²î±ðÔÚÄÄÀ

£¨×÷³ö²ÂÏ룩¢Ùº¬ÓÐ̼Ëá¸Æ£»¢Úº¬Óе°°×ÖÊ£»¢Ûº¬ÓÐ̼Ëá¸ÆºÍµ°°×ÖÊ

£¨ÊµÑéÒ»£©ÎªÁËÈ·ÈÏÕäÖé·ÛµÄ×é³É£¬Í¬Ñ§ÃǽøÐÐÁËÏÂÁÐʵÑ飺

²Ù×÷·½·¨

½áÂÛÓ뻯ѧ·´Ó¦·½³Ìʽ

ͨ¹ýa¡¢bʵÑé¼°ÆäËûÊֶΣ¬Ö¤Ã÷Á˶þÕß¶¼º¬ÓÐ̼Ëá¸Æ¡£bÖл¯Ñ§·´Ó¦·½³Ìʽ£º _________________

ÅжÏÕæ¡¢¼ÙÕäÖé·ÛÖÐÊÇ·ñº¬µ°°×Öʵķ½·¨ÊÇ£º ______________________

ÕæÕäÖé·ÛÖк¬Óе°°×ÖÊ£¬¼ÙÕäÖé·ÛÖв»º¬µ°°×ÖÊ¡£

£¨ÍØÕ¹ÊµÑ飩½«aÖÐÍêÈ«·´Ó¦ºóµÄ»ìºÏÎï¹ýÂË£¬²âµÃÂËÒºµÄ£¬ÊÇʲôÎïÖÊʹÂËÒºµÄ£¿Ð¡ÓðºÍСÎâ·ÖÎöºóÈÏΪֻÓÐÁ½ÖÖ¿ÉÄÜÐÔ²¢×÷Á˲ÂÏ룺²ÂÏë¢Ù£º·´Ó¦ºóÉú³ÉµÄ̼Ëá ²ÂÏë¢Ú£º·´Ó¦ºóÊ£ÓàµÄÑÎËá

£¨ÊµÑé¶þ£©Ð¡Ã÷ºÍСÎâÓÃÏÂÁÐʵÑé¶Ô²ÂÏë½øÐÐÑéÖ¤¡£

ʵÑé²Ù×÷

ʵÑéÏÖÏó

ʵÑé½áÂÛ

ÏòÕôÁóË®ÖÐͨÈë________ÖÁ±¥ºÍ£¬²âpH

pHԼΪ5.6

²ÂÏë¢Ù´íÎó

ÏòÂËÒºÖеÎÈëʯÈïÊÔÒº£¬È»ºó¼ÓÈÈÖÁ·ÐÌÚ

________________

²ÂÏë¢ÚÕýÈ·

д³ö²ÂÏë¢Ù·¢ÉúµÄ»¯Ñ§·´Ó¦·½³Ìʽ__________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø