题目内容
递等式计算.(能巧算的要巧算)
(1)253+468+347
(2)420÷5÷7
(3)112-112÷4.
(1)253+468+347
(2)420÷5÷7
(3)112-112÷4.
分析:(1)运用加法交换律解答,
(2)依据除法性质解答,
(3)按照先算除法,再算减法顺序解答.
(2)依据除法性质解答,
(3)按照先算除法,再算减法顺序解答.
解答:解:(1)253+468+347,
=253+347+468,
=600+468,
=1068;
(2)420÷5÷7,
=420÷7÷5,
=60÷5,
=12;
(3)112-112÷4,
=112-28,
=84.
=253+347+468,
=600+468,
=1068;
(2)420÷5÷7,
=420÷7÷5,
=60÷5,
=12;
(3)112-112÷4,
=112-28,
=84.
点评:本题考查知识点:(1)正确运用简便方法解决问题,(2)按照四则运算顺序正确进行计算.
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