题目内容
递等式计算.(能巧算的就巧算)
(1)167+133÷7
(2)536-274-136.
(1)167+133÷7
(2)536-274-136.
分析:(1)先算除法,再算加法.
(2)根据减法的性质简算.
(2)根据减法的性质简算.
解答:解:(1)167+133÷7,
=167+19,
=186;
(2)536-274-136,
=536-(274+136),
=536-410,
=126.
=167+19,
=186;
(2)536-274-136,
=536-(274+136),
=536-410,
=126.
点评:本题考查了简单的四则混合运算,计算时先理清楚运算顺序,根据运算顺序逐步求解即可.
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