题目内容
递等式计算,能简便的就简便计算.
35.8-6.35+3.65 | 4200÷25 | 200+144÷(16×3) |
280×36-360×18 | 5400÷(50×27) | [3920-(56+42×16)]÷28. |
分析:(1)先算减法,再算加法;
(2)25=5×5,再根据连除的性质进行计算;
(3)先算乘法,再算除法,最后算加法;
(4)根据乘法分配律进行计算;
(5)根据连除的性质进行计算;
(6)先算乘法,再算加法,再算减法.最后算除法.
(2)25=5×5,再根据连除的性质进行计算;
(3)先算乘法,再算除法,最后算加法;
(4)根据乘法分配律进行计算;
(5)根据连除的性质进行计算;
(6)先算乘法,再算加法,再算减法.最后算除法.
解答:解:
(1)35.8-6.35+3.65,
=29.45+3.65,
=33.1;
(2)4200÷25,
=4200÷(5×5),
=4200÷5÷5,
=840÷5,
=168;
(3)200+144÷(16×3),
=200+144÷48,
=200+3,
=203;
(4)280×36-360×18,
=280×36-36×180,
=(280-180)×36,
=100×36,
=3600;
(5)5400÷(50×27),
=5400÷50÷27,
=5400÷27÷50,
=200÷50,
=4;
(6)[3920-(56+42×16)]÷28,
=[3920-(56+672)]÷28,
=[3920-728]÷28,
=3192÷28,
=114.
(1)35.8-6.35+3.65,
=29.45+3.65,
=33.1;
(2)4200÷25,
=4200÷(5×5),
=4200÷5÷5,
=840÷5,
=168;
(3)200+144÷(16×3),
=200+144÷48,
=200+3,
=203;
(4)280×36-360×18,
=280×36-36×180,
=(280-180)×36,
=100×36,
=3600;
(5)5400÷(50×27),
=5400÷50÷27,
=5400÷27÷50,
=200÷50,
=4;
(6)[3920-(56+42×16)]÷28,
=[3920-(56+672)]÷28,
=[3920-728]÷28,
=3192÷28,
=114.
点评:此题主要考查分整数、小数的四则混合运算的运算顺序和应用运算定律进行简便计算.
练习册系列答案
相关题目