题目内容
脱式计算.(能简算的要简算)
|
4÷
|
| ||||||||||||||||||||
|
|
12-10÷7-
|
分析:(1)运用加法的交换律、结合律进行简算;
(2)先算除法,再算减法;
(3)把除法化成乘法,再运用乘法的分配律进行简算;
(4)先算小括号里的减法,再算中括号里的除法,最后算括号外的除法;
(5)先算小括号里的除法,再算小括号里的加法,最后算括号外的乘法;
(6)先算除法,再运用减法的性质进行解答.
(2)先算除法,再算减法;
(3)把除法化成乘法,再运用乘法的分配律进行简算;
(4)先算小括号里的减法,再算中括号里的除法,最后算括号外的除法;
(5)先算小括号里的除法,再算小括号里的加法,最后算括号外的乘法;
(6)先算除法,再运用减法的性质进行解答.
解答:解:(1)
+
+
+
=(
+
)+(
+
)
=1+2
=3
(2)4÷
-
÷4
=9-
=8
(3)
÷
+
÷
=
×
+
×
=
×(
+
)
=
×1
=
(4)
÷[(
-
)÷
]
=
÷[
÷
]
=
÷
=6
(5)
×(
+
÷
)
=
×(
+
)
=
×
=
(6)12-10÷7-
=12-
-
=12-(
+
)
=12-2
=10
5 |
9 |
3 |
11 |
4 |
9 |
19 |
11 |
=(
5 |
9 |
4 |
9 |
3 |
11 |
19 |
11 |
=1+2
=3
(2)4÷
4 |
9 |
4 |
9 |
=9-
1 |
9 |
=8
8 |
9 |
(3)
5 |
8 |
7 |
3 |
5 |
8 |
7 |
4 |
=
5 |
8 |
3 |
7 |
5 |
8 |
4 |
7 |
=
5 |
8 |
3 |
7 |
4 |
7 |
=
5 |
8 |
=
5 |
8 |
(4)
3 |
5 |
3 |
4 |
2 |
3 |
5 |
6 |
=
3 |
5 |
1 |
12 |
5 |
6 |
=
3 |
5 |
1 |
10 |
=6
(5)
7 |
15 |
4 |
21 |
8 |
15 |
7 |
10 |
=
7 |
15 |
4 |
21 |
16 |
21 |
=
7 |
15 |
20 |
21 |
=
4 |
9 |
(6)12-10÷7-
4 |
7 |
=12-
10 |
7 |
4 |
7 |
=12-(
10 |
7 |
4 |
7 |
=12-2
=10
点评:本题综合考查了学生的计算能力.注意第一题可用简便方法进行计算.
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