题目内容
计算 能简算则简算
|
1-
|
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|
|
|
分析:(1)运用加法交换律简算;
(2)根据连续减去两个数等于减去这两个数的和来简算;
(3)先通分,再按照从左到右的顺序计算;
(4)先去掉括号,再根据加法交换律简算;
(5)按照从左到右的顺序计算;
(6)先运用加法交换律交换加数的位置,再根据连续减去两个数等于减去这两个数的和来简算.
(2)根据连续减去两个数等于减去这两个数的和来简算;
(3)先通分,再按照从左到右的顺序计算;
(4)先去掉括号,再根据加法交换律简算;
(5)按照从左到右的顺序计算;
(6)先运用加法交换律交换加数的位置,再根据连续减去两个数等于减去这两个数的和来简算.
解答:解:(1)
+
+
,
=(
+
)+
,
=1+
,
=1
;
(2)1-
-
,
=1-(
+
),
=1-1,
=0;
(3)
+
+
,
=
+
+
,
=
+
,
=
;
(4)
-(
-
),
=
-
+
,
=(
+
)-
,
=1-
,
=
;
(5)
+
+
,
=1+
,
=1
;
(6)
-
+
-
,
=
+
-
-
,
=(
+
)-(
+
),
=
-
,
=
.
2 |
9 |
5 |
13 |
7 |
9 |
=(
2 |
9 |
7 |
9 |
5 |
13 |
=1+
5 |
13 |
=1
5 |
13 |
(2)1-
3 |
8 |
5 |
8 |
=1-(
3 |
8 |
5 |
8 |
=1-1,
=0;
(3)
1 |
3 |
3 |
4 |
5 |
24 |
=
8 |
24 |
18 |
24 |
5 |
24 |
=
26 |
24 |
5 |
24 |
=
31 |
24 |
(4)
7 |
9 |
2 |
3 |
2 |
9 |
=
7 |
9 |
2 |
3 |
2 |
9 |
=(
7 |
9 |
2 |
9 |
2 |
3 |
=1-
2 |
3 |
=
1 |
3 |
(5)
3 |
5 |
2 |
5 |
1 |
4 |
=1+
1 |
4 |
=1
1 |
4 |
(6)
4 |
5 |
2 |
3 |
4 |
5 |
2 |
3 |
=
4 |
5 |
4 |
5 |
2 |
3 |
2 |
3 |
=(
4 |
5 |
4 |
5 |
2 |
3 |
2 |
3 |
=
8 |
5 |
4 |
3 |
=
4 |
15 |
点评:本题考查了加减法的简便运算,要记住这些方法,并能灵活运用.

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