题目内容
计算下面各题,能简便的要简便计算. 7×
|
|
(
| ||||||||||||||||||||||
[1-(
|
(
|
|
分析:(1)按照先同时算乘法再算加法的顺序计算即可解答,
(2)按照从左到右的顺序计算即可解答,
(3)运用乘法分配律解答,
(4)按照先算小括号里面的,再算中括号里面的乘法,然后算中括号里面的减法,最后算括号外面的顺序计算即可解答,
(5)按照先算括号里面的,再同时计算乘法和除法,最后算减法顺序计算即可解答,
(6)运用乘法交换律即可解答.
(2)按照从左到右的顺序计算即可解答,
(3)运用乘法分配律解答,
(4)按照先算小括号里面的,再算中括号里面的乘法,然后算中括号里面的减法,最后算括号外面的顺序计算即可解答,
(5)按照先算括号里面的,再同时计算乘法和除法,最后算减法顺序计算即可解答,
(6)运用乘法交换律即可解答.
解答:解:(1)7×
+
×
=
+
=5
;
(2)
×
÷
=
÷
=
;
(3)(
+
-
)×36
=
×36+
×36-
×36
=15+4-10
=19-10
=9;
(4)[1-(
+
)×
]÷
=[1-
×
]÷
=[1-
]÷
=
÷
=1
;
(5)(
+
)÷
-
×
=
÷
-
×
=
-
=1
;
(6)
×(26×
)
=
×
×26
=
×26
=6.
7 |
9 |
2 |
7 |
5 |
9 |
=
49 |
9 |
10 |
63 |
=5
38 |
63 |
(2)
5 |
9 |
2 |
5 |
2 |
3 |
=
2 |
9 |
2 |
3 |
=
1 |
3 |
(3)(
5 |
12 |
1 |
9 |
5 |
18 |
=
5 |
12 |
1 |
9 |
5 |
18 |
=15+4-10
=19-10
=9;
(4)[1-(
1 |
5 |
2 |
3 |
4 |
13 |
11 |
20 |
=[1-
13 |
15 |
4 |
13 |
11 |
20 |
=[1-
4 |
15 |
11 |
20 |
=
11 |
15 |
11 |
20 |
=1
1 |
3 |
(5)(
1 |
8 |
1 |
6 |
5 |
24 |
2 |
3 |
1 |
4 |
=
7 |
24 |
5 |
24 |
2 |
3 |
1 |
4 |
=
7 |
5 |
1 |
6 |
=1
7 |
30 |
(6)
40 |
13 |
3 |
40 |
=
40 |
13 |
3 |
40 |
=
3 |
13 |
=6.
点评:本题主要考查学生依据四则运算计算方法正确进行计算,以及运用简便方法解决问题的能力.
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