题目内容
用递等式计算. (1)
|
(2)48048÷12+88 | ||||||||
(3)9÷(
|
(4)(1-0.8×
|
分析:依据四则运算顺序,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的顺序解答即可.
解答:解:(1)
÷
×
,
=
×
,
=2;
(2)48048÷12+88,
=4004+88,
=4092;
(3)9÷(
-
)×3,
=9÷
×3,
=81×3,
=243;
(4)(1-0.8×
)÷
,
=(1-0.6)÷
,
=0.4÷
,
=0.5.
5 |
6 |
1 |
4 |
3 |
5 |
=
10 |
3 |
3 |
5 |
=2;
(2)48048÷12+88,
=4004+88,
=4092;
(3)9÷(
7 |
9 |
2 |
3 |
=9÷
1 |
9 |
=81×3,
=243;
(4)(1-0.8×
3 |
4 |
4 |
5 |
=(1-0.6)÷
4 |
5 |
=0.4÷
4 |
5 |
=0.5.
点评:本题主要考查学生依据四则运算顺序,正确进行计算的能力,关键是计算结果要准确.
练习册系列答案
相关题目