题目内容

(2012?静宁县模拟)用递等式计算.
(1)370×203-19266÷38
(2)32×3.1+1÷1.25
(3)
21
26
×(39÷35)÷0.9
(4)(9-3.06÷
3
5
)×1
3
13

(5)(3-1
1
8
+1
1
7
)×1
8
13
-3
1
56
×56
(6)[(
37
40
+0.075)÷
3
25
-2
17
24
2
15
分析:(1)(2)(3)(4)(6)依据四则运算顺序,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的顺序解答,
(5)运用乘法分配律计算即可.
解答:解:(1)370×203-19266÷38,
=75110-507,
=74603;

(2)32×3.1+1÷1.25,
=9.92+0.8,
=10.72;

(3)
21
26
×(39÷35)÷0.9,
=
21
26
×
39
35
÷0.9,
=0.9÷0.9,
=1;

(4)(9-3.06÷
3
5
)×1
3
13

=(9-5.1)×1
3
13

=3.9×1
3
13

=4.8;

(5)(3-1
1
8
+1
1
7
)×1
8
13
-3
1
56
×56,
=3×56-1
1
8
×
56+1
1
7
×56,
=168-49+64,
=119+64,
=183;

(6)[(
37
40
+0.075)÷
3
25
-2
17
24
2
15

=[1÷
3
25
-2
17
24
2
15

=[
25
3
-2
17
24
2
15

=
135
24
×
2
15

=
3
4
点评:正确依据四则运算顺序进行计算,以及正确运用乘法分配律解决问题是本题考查知识点,注意计算结果的准确性.
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