题目内容
(2012?静宁县模拟)用递等式计算.
(1)370×203-19266÷38
(2)32×3.1+1÷1.25
(3)
×(39÷35)÷0.9
(4)(9-3.06÷
)×1
(5)(3-1
+1
)×1
-3
×56
(6)[(
+0.075)÷
-2
]×
.
(1)370×203-19266÷38
(2)32×3.1+1÷1.25
(3)
21 |
26 |
(4)(9-3.06÷
3 |
5 |
3 |
13 |
(5)(3-1
1 |
8 |
1 |
7 |
8 |
13 |
1 |
56 |
(6)[(
37 |
40 |
3 |
25 |
17 |
24 |
2 |
15 |
分析:(1)(2)(3)(4)(6)依据四则运算顺序,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的顺序解答,
(5)运用乘法分配律计算即可.
(5)运用乘法分配律计算即可.
解答:解:(1)370×203-19266÷38,
=75110-507,
=74603;
(2)32×3.1+1÷1.25,
=9.92+0.8,
=10.72;
(3)
×(39÷35)÷0.9,
=
×
÷0.9,
=0.9÷0.9,
=1;
(4)(9-3.06÷
)×1
,
=(9-5.1)×1
,
=3.9×1
,
=4.8;
(5)(3-1
+1
)×1
-3
×56,
=3×56-1
×56+1
×56,
=168-49+64,
=119+64,
=183;
(6)[(
+0.075)÷
-2
]×
,
=[1÷
-2
]×
,
=[
-2
]×
,
=
×
,
=
.
=75110-507,
=74603;
(2)32×3.1+1÷1.25,
=9.92+0.8,
=10.72;
(3)
21 |
26 |
=
21 |
26 |
39 |
35 |
=0.9÷0.9,
=1;
(4)(9-3.06÷
3 |
5 |
3 |
13 |
=(9-5.1)×1
3 |
13 |
=3.9×1
3 |
13 |
=4.8;
(5)(3-1
1 |
8 |
1 |
7 |
8 |
13 |
1 |
56 |
=3×56-1
1 |
8 |
1 |
7 |
=168-49+64,
=119+64,
=183;
(6)[(
37 |
40 |
3 |
25 |
17 |
24 |
2 |
15 |
=[1÷
3 |
25 |
17 |
24 |
2 |
15 |
=[
25 |
3 |
17 |
24 |
2 |
15 |
=
135 |
24 |
2 |
15 |
=
3 |
4 |
点评:正确依据四则运算顺序进行计算,以及正确运用乘法分配律解决问题是本题考查知识点,注意计算结果的准确性.
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