题目内容
计算下面各题,能简便的要用简便方法计算.
(
|
4-
|
|
|
分析:(1)根据乘法分配律进行简算即可;
(2)先算除法,再根据连续减去两个数等于减去这两个数的和进行计算;
(3)根据乘法分配律进行简算;
(4)先算小括号里面的加法,再算除法,最后算乘法.
(2)先算除法,再根据连续减去两个数等于减去这两个数的和进行计算;
(3)根据乘法分配律进行简算;
(4)先算小括号里面的加法,再算除法,最后算乘法.
解答:解:
(1)(
+
)×15,
=
×15+
×15,
=3+10,
=13;
(2)4-
÷
-
,
=4-
-
,
=4-(
+
),
=4-1,
=3;
(3)
×
-
÷5,
=
×
-
×
,
=(
-
)×
,
=1×
,
=
;
(4)
÷(
+
)×
,
=
÷
×
,
=
×
,
=
.
(1)(
1 |
5 |
2 |
3 |
=
1 |
5 |
2 |
3 |
=3+10,
=13;
(2)4-
9 |
15 |
9 |
5 |
2 |
3 |
=4-
1 |
3 |
2 |
3 |
=4-(
1 |
3 |
2 |
3 |
=4-1,
=3;
(3)
6 |
5 |
6 |
7 |
6 |
7 |
=
6 |
5 |
6 |
7 |
6 |
7 |
1 |
5 |
=(
6 |
5 |
1 |
5 |
6 |
7 |
=1×
6 |
7 |
=
6 |
7 |
(4)
7 |
4 |
2 |
3 |
1 |
2 |
4 |
5 |
=
7 |
4 |
7 |
6 |
4 |
5 |
=
3 |
2 |
4 |
5 |
=
6 |
5 |
点评:根据题意,先找清运算顺序,然后再进一步计算即可,能简算的要简算.
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