题目内容

计算
9
20
÷[
1
2
×(
2
5
+
4
5
)]
②(0.4+
2
3
)÷(
5
6
-0.75)×0.5
③1.25+1
1
4
×7.4+125%÷
5
8

393939×899899
377377×939393

⑤6.6-1
3
5
÷(0.375×
4
5
+
1
8
×0.8)
5
1
4
-2.125+(4.75-3
3
8

1
1
24
+[(1.5+2
2
3
)÷3.75-
2
3
8
9

1
1×4
+
1
4×7
+
1
7×10
+…+
1
97×100
分析:①先算加法,再算乘法,最后算除法;
②先算加法和减法,再算除法,最后算乘法;
③根据乘法分配律进行计算;
④把393939、899899、377377和939393分解质因数,然后再进行约分即可;
⑤根据此乘法分配律进行计算;
⑥根据加法交换律和结合律进行计算;
⑦先算小括号里面的加法,再算中括号里面的除法,再算中括号里面的减法,再算括号外面的除法,最后算括号外面的加法;
⑧根据分数的拆项进行计算.
解答:解:
9
20
÷[
1
2
×(
2
5
+
4
5
)],
=
9
20
÷[
1
2
×
6
5
],
=
9
20
÷
3
5

=
3
4


②(0.4+
2
3
)÷(
5
6
-0.75)×0.5,
=
16
15
÷
1
12
×0.5,
=
64
5
×0.5,
=6.4;

③1.25+1
1
4
×7.4+125%÷
5
8

=1.25+1.25×7.4+1.25×1.6,
=1.25×(1+7.4+1.6),
=1.25×10,
=12.5;

393939×899899
377377×939393

=
(3×13×10101)×(29×31×1001)
(13×29×1001)×(3×31×10101)

=
3×13××29×31×1001×10101
3×13×29×31×1001×10101

=1;

⑤6.6-1
3
5
÷(0.375×
4
5
+
1
8
×0.8),
=6.6-1
3
5
÷(0.375×0.8+
1
8
×0.8),
=6.6-1
3
5
÷[(0.375+
1
8
)×0.8],
=6.6-1
3
5
÷[0.5×0.8],
=6.6-1
3
5
÷0.4,
=6.6-4,
=2.6;

5
1
4
-2.125+(4.75-3
3
8
),
=5.25-2.125+4.75-3.375,
=(5.25+4.75)-(2.125+3.375),
=10-5.5,
=4.5;

1
1
24
+[(1.5+2
2
3
)÷3.75-
2
3
8
9

=1
1
24
+[
25
6
÷3.75-
2
3
8
9

=1
1
24
+[
10
9
-
2
3
8
9

=1
1
24
+
2
3
÷
8
9

=1
1
24
+
3
4

=1
19
24


1
1×4
+
1
4×7
+
1
7×10
+…+
1
97×100

=
1
3
×(1-
1
4
+
1
4
-
1
7
+
1
7
-
1
10
+…+
1
97
-
1
100
),
=
1
3
×(1-
1
100
),
=
1
3
×
99
100

=
33
100
点评:四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
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