题目内容
8.脱式计算,能简算的要简算[1.9+19%×(5.8-4$\frac{4}{5}$)]÷(53×$\frac{1}{4}$+30.6×0.25)
12-[$\frac{1}{5}$-(35%-$\frac{1}{10}$)×$\frac{1}{5}$]
62.8×19-8×62$\frac{4}{5}$-62$\frac{4}{5}$
[(2$\frac{2}{3}$-1.5)÷$\frac{5}{6}$+2$\frac{1}{2}$]÷$\frac{8}{9}$.
分析 (1)先算小括号里的减法,再算中括号里的乘法,再算中括号里的加法,53×$\frac{1}{4}$+30.6×0.25运用乘法的分配律进行简算,最后算括号外的除法;
(2)先算小括号里的减法,再算中括号里的乘法,再算中括号里的减法,最后算括号外的减法;
(3)运用乘法的分配律进行简算;
(4)把中括号里的除以$\frac{5}{6}$化成乘以$\frac{6}{5}$,再运用乘法的分配律进行简算,先算小括号里的减法,再算中括号里的除法,再算中括号里的加法,最后算括号外的除法.
解答 解:(1)[1.9+19%×(5.8-4$\frac{4}{5}$)]÷(53×$\frac{1}{4}$+30.6×0.25)
=[1.9+19%×1]÷[(53+30.6)×0.25]
=[1.9+19%]÷[83.6×0.25]
=2.09÷20.9
=0.1;
(2)12-[$\frac{1}{5}$-(35%-$\frac{1}{10}$)×$\frac{1}{5}$]
=12-[$\frac{1}{5}$-$\frac{1}{4}$×$\frac{1}{5}$]
=12-[$\frac{1}{5}$-$\frac{1}{20}$]
=12-$\frac{3}{20}$
=11$\frac{17}{20}$;
(3)62.8×19-8×62$\frac{4}{5}$-62$\frac{4}{5}$
=62.8×(19-8-1)
=62$\frac{4}{5}$×10
=628;
(4)[(2$\frac{2}{3}$-1.5)÷$\frac{5}{6}$+2$\frac{1}{2}$]÷$\frac{8}{9}$
=[(2$\frac{2}{3}$-1.5)×$\frac{6}{5}$+2$\frac{1}{2}$]÷$\frac{8}{9}$
=[(2$\frac{2}{3}$×$\frac{6}{5}$-1.5×$\frac{6}{5}$)+2$\frac{1}{2}$]÷$\frac{8}{9}$
=[(3.2-1.8)+2$\frac{1}{2}$]÷$\frac{8}{9}$
=[1.4+2$\frac{1}{2}$]÷$\frac{8}{9}$
=3.9÷$\frac{8}{9}$
=4.3875.
点评 此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
A. | 米 | B. | 平方米 | C. | 平方分米 | D. | 立方米 |
A. | 200 | B. | 310 | C. | 224 |
直接写出得数. 680+320= | 287+199= | 15×6= | 64+1.36= |
3.5+6.5= | 10-0.9= | 24×5= | 3.7-2.5= |
4×(25×7)= | 1+0.46-0.46= | 39.01+20.18≈ | 55.3-34.84≈ |
547+398= | 423-299= | 800×125= | 300÷15= |
16×50= | 58×5×2= | (37+43)÷40= | 720÷8÷9= |
A. | 1:12 | B. | 1:60 | C. | 60:1 |