题目内容
计算:
(1)3.75×4.23×36-125×0.423×2.8
(2)
+
+
+…+
+
-
-
-…-
-
(3)如:a※b=2a-b成立,已知x※(4※1)=6,求x.
(4)1030×0.125+44.3×12.5+262×1.25.
(1)3.75×4.23×36-125×0.423×2.8
(2)
1 |
110 |
2 |
110 |
3 |
110 |
9 |
110 |
10 |
110 |
11 |
465 |
12 |
465 |
19 |
465 |
20 |
465 |
(3)如:a※b=2a-b成立,已知x※(4※1)=6,求x.
(4)1030×0.125+44.3×12.5+262×1.25.
分析:(1)根据题意,把3.75拆成12.5×0.3,125×0.423×2.8根据积不变的规律,看作12.5×4.23×2.8,然后再根据乘法分配律进行计算即可;
(2)把
+
+
+…+
+
和
+
+…+
+
分别求出来,再进一步计算即可;
(3)根据新定义的法则,a※b=2a-b成立,也就前一个数的2倍减去后面一个数,这种计算方法,再进一步计算即可;
(4)根据积不变的规律可知,1030×0.125=103×1.25,44.3×12.5=443×1.25,再根据乘法分配律进行计算即可.
(2)把
1 |
110 |
2 |
110 |
3 |
110 |
9 |
110 |
10 |
110 |
11 |
465 |
12 |
465 |
19 |
465 |
20 |
465 |
(3)根据新定义的法则,a※b=2a-b成立,也就前一个数的2倍减去后面一个数,这种计算方法,再进一步计算即可;
(4)根据积不变的规律可知,1030×0.125=103×1.25,44.3×12.5=443×1.25,再根据乘法分配律进行计算即可.
解答:解:(1)3.75×4.23×36-125×0.423×2.8,
=3.75×4.23×36-12.5×4.23×2.8,
=4.23×(3.75×36-12.5×2.8),
=4.23×(12.5×0.3×36-12.5×2.8),
=4.23×12.5×(0.3×36-2.8),
=4.23×12.5×(10.8-2.8),
=4.23×12.5×8,
=423;
(2))
+
+
+…+
+
-
-
-…-
-
,
=(
+
+
+…+
+
)-(
+
+…+
+
),
=
-
,
=
-
,
=
-
,
=
-
,
=
;
(3)根据题意可得:
4※1=4×2-1=7;
x※(4※1)=x※7=2x-7=6;
2x-7=6,
2x-7+7=6+7
2x=13
2x÷2=13÷2
x=6.5;
(4)1030×0.125+44.3×12.5+262×1.25,
=103×1.25+443×1.25+262×1.25,
=(103+443+262)×1.25,
=808×1.25,
=(800+8)×1.25,
=800×1.25+8×1.25,
=1000+10,
=1010.
=3.75×4.23×36-12.5×4.23×2.8,
=4.23×(3.75×36-12.5×2.8),
=4.23×(12.5×0.3×36-12.5×2.8),
=4.23×12.5×(0.3×36-2.8),
=4.23×12.5×(10.8-2.8),
=4.23×12.5×8,
=423;
(2))
1 |
110 |
2 |
110 |
3 |
110 |
9 |
110 |
10 |
110 |
11 |
465 |
12 |
465 |
19 |
465 |
20 |
465 |
=(
1 |
110 |
2 |
110 |
3 |
110 |
9 |
110 |
10 |
110 |
11 |
465 |
12 |
465 |
19 |
465 |
20 |
465 |
=
1+2+3+…+9+10 |
110 |
11+12+…+19+20 |
465 |
=
(1+10)×10÷2 |
110 |
(11+20)×10÷2 |
465 |
=
55 |
110 |
155 |
465 |
=
1 |
2 |
1 |
3 |
=
1 |
6 |
(3)根据题意可得:
4※1=4×2-1=7;
x※(4※1)=x※7=2x-7=6;
2x-7=6,
2x-7+7=6+7
2x=13
2x÷2=13÷2
x=6.5;
(4)1030×0.125+44.3×12.5+262×1.25,
=103×1.25+443×1.25+262×1.25,
=(103+443+262)×1.25,
=808×1.25,
=(800+8)×1.25,
=800×1.25+8×1.25,
=1000+10,
=1010.
点评:巧算这些题目,要选择好所运用的运算定律,然后再进一步计算即可.
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