题目内容

用递等式计算
(1)12.6-0.84×5÷1.4(2)2.8×0.25+7.2×0.25(3)7.24×[1÷(3.1-3.09)]
(4)0.18×(4.6-0.598÷0.46)(5)4.83×0.7+3×0.483(6)8.625÷[(17.2-16.2)÷0.04].

解:(1)12.6-0.84×5÷1.4,
=12.6-4.2÷1.4,
=12.6-3,
=9.6;

(2)2.8×0.25+7.2×0.25,
=(2.8+7.2)×0.25,
=10×0.25,
=2.5;

(3)7.24×[1÷(3.1-3.09)],
=7.24×[1÷0.01],
=7.24×100,
=724;

(4)0.18×(4.6-0.598÷0.46),
=0.18×(4.6-1.3),
=0.18×3.3,
=0.594;

(5)4.83×0.7+3×0.483,
=4.83×0.7+0.3×4.83,
=4.83×(0.7+0.3),
=4.83×1,
=4.83;

(6)8.625÷[(17.2-16.2)÷0.04],
=8.625÷[1÷0.04],
=8.625÷25,
=0.345.
分析:(1)(3)(4)(6)根据四则运算的计算顺序进行计算,
(2)(4)根据乘法分配律进行解答.
点评:本题主要考查了学生在四则运算中灵活运用简便算法的计算能力.
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