题目内容
解方程.
5x-3×
=
5-
x=
2x+40%x=7.2
5×(x-
)=2.
5x-3×
10 |
7 |
7 |
5 |
5-
2 |
3 |
1 |
3 |
2x+40%x=7.2
5×(x-
1 |
3 |
分析:根据等式的性质解答,即“等式两边同时乘同一个数,或除以同一个不为0的数,结果仍相等”,“等式两边同时加上(或减去)同一个数(或式子),结果仍相等”.
解答:解:(1)5x-3×
=
,
5x-3×
+ 3×
=
+3×
,
5x=
,
5x÷5=
÷5,
x=1
;
(2)5-
x=
,
5-
x+
x=
+
x,
+
x=5,
+
x-
=5-
,
x×
=
×
,
x=7;
(3)2x+40%x=7.2,
2.4x=7.2,
2.4x÷2.4=7.2÷2.4,
x=3;
(4)5×(x-
)=2,
5×(x-
)÷5=2÷5,
x-
=
,
x-
+
=
+
,
x=
.
10 |
7 |
7 |
5 |
5x-3×
10 |
7 |
10 |
7 |
7 |
5 |
10 |
7 |
5x=
199 |
35 |
5x÷5=
199 |
35 |
x=1
24 |
175 |
(2)5-
2 |
3 |
1 |
3 |
5-
2 |
3 |
2 |
3 |
1 |
3 |
2 |
3 |
1 |
3 |
2 |
3 |
1 |
3 |
2 |
3 |
1 |
3 |
1 |
3 |
2 |
3 |
3 |
2 |
14 |
3 |
3 |
2 |
x=7;
(3)2x+40%x=7.2,
2.4x=7.2,
2.4x÷2.4=7.2÷2.4,
x=3;
(4)5×(x-
1 |
3 |
5×(x-
1 |
3 |
x-
1 |
3 |
2 |
5 |
x-
1 |
3 |
1 |
3 |
2 |
5 |
1 |
3 |
x=
11 |
15 |
点评:考查了学生利用等式的性质解方程的能力,注意等号对齐.
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