题目内容
递等式计算,能简便的要简便. 25×32×0.25 |
0.25×(0.4+40) | 0.67+1.28+9.33+0.72 |
3.18-(0.33+1.18) | 6.3÷35 | [1-(0.5-0.25)]×0.6 |
7.8×0.9+0.78 | 7.8×0.9+0.78 | 1.9-1.9×(1.9-1.9) |
分析:(1)把32看作4×4×2,运用乘法分交换律与结合率简算;
(2)运用乘法分配律简算;
(3)运用加法交换律与结合律简算;
(4)运用剑法的性质以及加法交换律与结合律简算;
(5)把35看作7×5,运用除法的性质简算;
(6)先算小括号内的,再算中括号内的,最后算括号外的;
(7)通过数字转化,运用乘法分配律简算;
(8)括号内的结果为0,因此本题结果为1.9.
(2)运用乘法分配律简算;
(3)运用加法交换律与结合律简算;
(4)运用剑法的性质以及加法交换律与结合律简算;
(5)把35看作7×5,运用除法的性质简算;
(6)先算小括号内的,再算中括号内的,最后算括号外的;
(7)通过数字转化,运用乘法分配律简算;
(8)括号内的结果为0,因此本题结果为1.9.
解答:解:(1)25×32×0.25
=25×4×2×4×0.25
=(25×4)×(4×0.25)×2
=100×1×2
=200;
(2)0.25×(0.4+40)
=0.25×0.4+40×0.25
=0.1+10
=10.1;
(3)0.67+1.28+9.33+0.72
=(0.67+9.33)+(1.28+0.72)
=10+2
=12;
(4)3.18-(0.33+1.18)
=3.18-0.33-1.18
=(3.18-1.18)-0.33
=2-0.33
=1.67;
(5)6.3÷35
=6.3÷(7×5)
=(6.3÷7)÷5
=0.9÷5
=0.18;
(6)[1-(0.5-0.25)]×0.6
=[1-0.25]×0.6
=0.75×0.6
=0.45;
(7)7.8×0.9+0.78
=0.78×9+0.78
=0.78×(9+1)
=0.78×10
=7.8;
(8)1.9-1.9×(1.9-1.9)
=1.9-1.9×0
=1.9-0
=1.9.
=25×4×2×4×0.25
=(25×4)×(4×0.25)×2
=100×1×2
=200;
(2)0.25×(0.4+40)
=0.25×0.4+40×0.25
=0.1+10
=10.1;
(3)0.67+1.28+9.33+0.72
=(0.67+9.33)+(1.28+0.72)
=10+2
=12;
(4)3.18-(0.33+1.18)
=3.18-0.33-1.18
=(3.18-1.18)-0.33
=2-0.33
=1.67;
(5)6.3÷35
=6.3÷(7×5)
=(6.3÷7)÷5
=0.9÷5
=0.18;
(6)[1-(0.5-0.25)]×0.6
=[1-0.25]×0.6
=0.75×0.6
=0.45;
(7)7.8×0.9+0.78
=0.78×9+0.78
=0.78×(9+1)
=0.78×10
=7.8;
(8)1.9-1.9×(1.9-1.9)
=1.9-1.9×0
=1.9-0
=1.9.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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