题目内容
用递等式计算
0.36×11
+13
÷
18
-(7
-2
)-
÷
0.56÷[(3.6×
-1.5)×4.4+5.6].
0.36×11
4 |
7 |
3 |
7 |
7 |
9 |
18
5 |
9 |
5 |
13 |
1 |
3 |
8 |
13 |
1 |
2 |
0.56÷[(3.6×
5 |
12 |
(1)0.36×11
+13
÷
,
=
×
+
×
,
=
+
,
+
,
=
,
=21
;
(2)18
-(7
-2
)-
÷
,
=18
-5
-
×2,
=18
-5
-
,
=18
-5
-
,
=12
;
(3)0.56÷[(3.6×
-1.5)×4.4+5.6],
=0.56÷[(1.5-1.5)×4.4+5.6],
=0.56÷[0×4.4+5.6],
=0.56÷5.6,
=0.1.
4 |
7 |
3 |
7 |
7 |
9 |
=
9 |
25 |
81 |
7 |
94 |
7 |
9 |
7 |
=
729 |
175 |
846 |
49 |
5103 |
1225 |
21150 |
1225 |
=
26253 |
1225 |
=21
528 |
1225 |
(2)18
5 |
9 |
5 |
13 |
1 |
3 |
8 |
13 |
1 |
2 |
=18
5 |
9 |
2 |
39 |
8 |
13 |
=18
5 |
9 |
2 |
39 |
16 |
13 |
=18
65 |
117 |
6 |
117 |
144 |
117 |
=12
32 |
117 |
(3)0.56÷[(3.6×
5 |
12 |
=0.56÷[(1.5-1.5)×4.4+5.6],
=0.56÷[0×4.4+5.6],
=0.56÷5.6,
=0.1.
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