题目内容
计算下面各题,能简便计算的要简便计算. 10.15-6.25-3.75 | 1.75-(0.75+) | 9×+×3 |
+÷+ | 1÷(2.5×) | 6.48÷[(3.3-2.7)×0.9]. |
解:(1)10.15-6.25-3.75,
=10.15-(6.25+3.75),
=10.15-10,
=0.15;
(2)1.75-(0.75+),
=1.75-0.75-0.4,
=1-0.4,
=0.6;
(3)9×+3,
=(9+3)×,
=12×,
=;
(4),
=()+,
=1+,
=1;
(5)1÷(2.5×),
=(×),
=2,
=,
=;
(6)6.48÷[(3.3-2.7)×0.9],
=6.48÷[0.6×0.9],
=6.48÷0.6÷0.9,
=10.8÷0.9,
=12.
分析:(1)(2)题利用减法的性质简算;
(3)运用乘法分配律的逆运算简算;
(4)先运用加法交换律和结合律把原式变为()+,计算即可;
(5)按运算顺序进行计算,先算括号内的,再算括号外的;
(6)先按运算顺序进行计算,算出小括号内的结果,原式变为6.48÷[0.6×0.9],根据数字特点,运用除法的性质简算.
点评:在解答计算题时,要注意审题,仔细观察,抓住特点,巧妙解答.
=10.15-(6.25+3.75),
=10.15-10,
=0.15;
(2)1.75-(0.75+),
=1.75-0.75-0.4,
=1-0.4,
=0.6;
(3)9×+3,
=(9+3)×,
=12×,
=;
(4),
=()+,
=1+,
=1;
(5)1÷(2.5×),
=(×),
=2,
=,
=;
(6)6.48÷[(3.3-2.7)×0.9],
=6.48÷[0.6×0.9],
=6.48÷0.6÷0.9,
=10.8÷0.9,
=12.
分析:(1)(2)题利用减法的性质简算;
(3)运用乘法分配律的逆运算简算;
(4)先运用加法交换律和结合律把原式变为()+,计算即可;
(5)按运算顺序进行计算,先算括号内的,再算括号外的;
(6)先按运算顺序进行计算,算出小括号内的结果,原式变为6.48÷[0.6×0.9],根据数字特点,运用除法的性质简算.
点评:在解答计算题时,要注意审题,仔细观察,抓住特点,巧妙解答.
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