题目内容
脱式计算.(能简算的要写出简算的主要过程) 12×(
|
920÷40+23×99 | ||||||||||
|
|
分析:(1)根据乘法分配律进行计算;
(2)把920变形为(23×40),再根据乘法分配律进行计算;
(3)先把括号内的式子变形,再根据乘法分配律进行计算;
(4)根据四则混合运算的计算顺序进行计算.
(2)把920变形为(23×40),再根据乘法分配律进行计算;
(3)先把括号内的式子变形,再根据乘法分配律进行计算;
(4)根据四则混合运算的计算顺序进行计算.
解答:解:(1)12×(
+
-
),
=12×
+12×
-12×
,
=3+9-2,
=10;
(2)920÷40+23×99,
=23×40÷40+23×99,
=23+23×99,
=23×(1+99),
=23×100,
=2300;
(3)
×(4.85÷
-3.6+6.15×3
),
=
×(4.85×3.6-3.6+6.15×3.6),
=
×{(4.85-1+6.15)×3.6],
=
×[10×3.6],
=
×36,
=9;
(4)
×[0.75-(
+25%)],
=
×[0.75-
],
=
×
,
=
.
1 |
4 |
3 |
4 |
1 |
6 |
=12×
1 |
4 |
3 |
4 |
1 |
6 |
=3+9-2,
=10;
(2)920÷40+23×99,
=23×40÷40+23×99,
=23+23×99,
=23×(1+99),
=23×100,
=2300;
(3)
1 |
4 |
5 |
18 |
3 |
5 |
=
1 |
4 |
=
1 |
4 |
=
1 |
4 |
=
1 |
4 |
=9;
(4)
4 |
9 |
7 |
16 |
=
4 |
9 |
11 |
16 |
=
4 |
9 |
1 |
16 |
=
1 |
36 |
点评:本题主要考查了学生在四则混合运算中灵活运用简便算法的能力.
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