题目内容
0.888×125×73+999×3=________.
11100
分析:原式化成0.111×8×125×73+111×9×3=0.111×(8×125)×73+111×(9×3)=0.111×1000×73+111×27,再运用乘法的分配律进行简算即可.
解答:0.888×125×73+999×3,
=0.111×8×125×73+111×9×3,
=0.111×(8×125)×73+111×(9×3),
=0.111×1000×73+111×27,
=111×73+111×27,
=111×(73+27),
=111×100,
=11100;
故答案为:11100.
点评:考查了灵活运用乘法的分配律进行简算.
分析:原式化成0.111×8×125×73+111×9×3=0.111×(8×125)×73+111×(9×3)=0.111×1000×73+111×27,再运用乘法的分配律进行简算即可.
解答:0.888×125×73+999×3,
=0.111×8×125×73+111×9×3,
=0.111×(8×125)×73+111×(9×3),
=0.111×1000×73+111×27,
=111×73+111×27,
=111×(73+27),
=111×100,
=11100;
故答案为:11100.
点评:考查了灵活运用乘法的分配律进行简算.
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