题目内容

0.125×32×25 128×99
32
3
-(3.14+
2
3
5
6
-
3
4
)÷
5
12
+
9
5
4
7
+
3
8
+
1
8
+
5
7
1
2
+
1
3
÷
2
3
10.9-1.6-3
2
5
1
4
÷(
4
3
-
1
2
4
25
÷
25
12
6.5×99+6.5
1
2
+
1
3
+
1
6
)×24
123×5.67+8.77×567
2-
7
15
×
9
14
2-
5
11
÷
9
22
-
8
9
3
4
÷(1-
1
2
-
3
8
49×
5
48
2
3
+
1
8
)×(1-
9
19
9
3
4
+99
3
4
+999
3
4
+9999
3
4
分析:(1)化32=8×4,再运用乘法结合律解答,
(2)(4)(10)(11)(12)(16)运用乘法分配律解答,
(3)(7)(14)依据减法的性质解答,
(5)运用加法交换律和结合律解答,
(6)(8)(13)(15)(17)依据四则运算计算方法解答,
(9)运用除法的性质解答,
(18)根据整数部分与整数部分,分数部分与分数部分相加解答.
解答:解:(1)0.125×32×25,
=(0.125×8)×(4×25),
=1×100,
=100;

(2)128×99,
=128×(100-1),
=128×100-128×1,
=12800-128,
=12672;

(3)
32
3
-(3.14+
2
3
),
=10
2
3
-3.14-
2
3

=10-3.14,
=6.86;

(4)(
5
6
-
3
4
)÷
5
12
+
9
5

=
5
6
÷
5
12
-
3
4
÷
5
12
+
9
5

=2-
9
5
+
9
5

=2;

(5)
4
7
+
3
8
+
1
8
+
5
7

=(
4
7
+
5
7
)+(
3
8
+
1
8
),
=
9
7
+
1
2

=1
11
14


(6)
1
2
+
1
3
÷
2
3

=
1
2
+
1
2

=1;

(7)10.9-1.6-3
2
5

=10.9-(1.6+3.4),
=10.9-5,
=5.9;

(8)
1
4
÷(
4
3
-
1
2
),
=
1
4
÷
5
6

=0.3;

(9)2÷
4
25
÷
25
12

=2÷(
4
25
×
25
12
),
=2÷
1
3

=6;

(10)6.5×99+6.5,
=6.5×(99+1),
=6.5×100,
=650;

(11)(
1
2
+
1
3
+
1
6
)×24,
=
1
2
×24+
1
3
×24+
1
6
×24,
=12+8+4,
=20+4,
=24;

(12)123×5.67+8.77×567,
=5.67×(123+877),
=5.67×1000,
=5670;

(13)2-
7
15
×
9
14

=2-0.3,
=1.7;

(14)2-
5
11
÷
9
22
-
8
9

=2-(
10
9
+
8
9
),
=2-2,
=0;

(15)
3
4
÷(1-
1
2
-
3
8
),
=
3
4
÷(
1
2
-
3
8
),
=
3
4
÷
1
8

=6;

(16)49×
5
48

=(48+1)×
5
48

=48×
5
48
+1×
5
48

=5+
5
48

=5
5
48


(17)(
2
3
+
1
8
)×(1-
9
19
),
=
19
24
×
10
19

=
5
12


(18)9
3
4
+99
3
4
+999
3
4
+9999
3
4

=(9+99+999+9999)+(
3
4
×4),
=9++(99+1)+(999+1)+(9999+1),
=9+100+1000+10000,
=11109.
点评:本题主要考查了学生运用四则运算计算方法,以及简便算法解决问题的能力
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