题目内容
用递等式计算.
60-25×4.5×0.4
3×(150-1530÷15)
÷[(
+
)×
].
60-25×4.5×0.4
3×(150-1530÷15)
8 |
9 |
2 |
5 |
1 |
10 |
3 |
4 |
分析:第一题要灵活运用乘法交换律;后两题要先算过号里的.
解答:解:60-25×4.5×0.4,
=60-25×0.4×4.5,
=60-10×4.5,
=60-45,
=15.
3×(150-1530÷15),
=3×(150-102),
=3×48,
=144.
÷[(
+
)×
],
=
÷[(
+
)×
],
=
÷[
×
],
=
÷
,
=
×
,
=
.
=60-25×0.4×4.5,
=60-10×4.5,
=60-45,
=15.
3×(150-1530÷15),
=3×(150-102),
=3×48,
=144.
8 |
9 |
2 |
5 |
1 |
10 |
3 |
4 |
=
8 |
9 |
4 |
10 |
1 |
10 |
3 |
4 |
=
8 |
9 |
1 |
2 |
3 |
4 |
=
8 |
9 |
3 |
8 |
=
8 |
9 |
8 |
3 |
=
64 |
27 |
点评:在四则混合运算中要注意运算顺序,特别是带括号的,还要在计算过程中合理地运用简算.
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