题目内容

用递等式进行计算,能简便的要简便简便计算.
0.25×(0.4+40)0.67+1.28+9.33+0.72
3.18-(0.33+1.18)[1-(0.5-0.25)]×0.6

解:(1)0.25×(0.4+40),
=0.25×0.4+0.25×40,
=0.1+10,
=10.1;

(2)0.67+1.28+9.33+0.72,
=(0.67+9.33)+(1.28+0.72),
=10+2,
=12;

(3)3.18-(0.33+1.18),
=3.18-0.33-1.18,
=(3.18-1.18)-0.33,
=2-0.33,
=1.67;

(4)[1-(0.5-0.25)]×0.6,
=[1-0.25]×0.6,
=0.75×0.6,
=0.45.
分析:(1)根据乘法分配律进行简算;
(2)根据加法交换律和结合律进行简算;
(3)把括号去掉.原式=3.18-0.33-1.18,再根据加法交换律和结合律进行简算;
(4)先计算小括号里面的减法,再计算中括号里面的减法,最后计算乘法.
点评:四则混合运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
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