题目内容
基本计算
(1)10.6-(6.6+0.125+12.5%)
(2)(4
+0.8+3
)×1.25
(3)12×(
+
)+5÷17
(4)3-
.
(1)10.6-(6.6+0.125+12.5%)
(2)(4
5 |
9 |
4 |
9 |
(3)12×(
1 |
60 |
1 |
17 |
(4)3-
1993+1992×1994 |
1993×1994-1 |
分析:(1)先把10.6和6.6结合,然后按运算顺序计算;
(2)括号内运用加法交换律和结合律简算,然后云用乘法分配律简算;
(3)把除法改为乘法,原式变为12×
+12×
+5×
,然后把后两项运用乘法分配律的逆运算简算;
(4)此题分数的分子与分母很有特点,通过拆分,运用乘法分配律,发现分子与分母相同,计算得出结果.
(2)括号内运用加法交换律和结合律简算,然后云用乘法分配律简算;
(3)把除法改为乘法,原式变为12×
1 |
60 |
1 |
17 |
1 |
17 |
(4)此题分数的分子与分母很有特点,通过拆分,运用乘法分配律,发现分子与分母相同,计算得出结果.
解答:解:(1)10.6-(6.6+0.125+12.5%),
=(10.6-6.6)-(0.125+0.125),
=4-0.25,
=3.75;
(2)(4
+0.8+3
)×1.25,
=[(4
+3
)+0.8]×1.25,
=[8+0.8]×1.25,
=8×1.25+0.8×1.25,
=10+1,
=11;
(3)12×(
+
)+5÷17,
=12×
+12×
+5×
,
=
+(12+5)×
,
=
+17×
,
=
+1,
=1
;
(4)3-
,
=3-
,
=3-
,
=3-
,
=3-1,
=2.
=(10.6-6.6)-(0.125+0.125),
=4-0.25,
=3.75;
(2)(4
5 |
9 |
4 |
9 |
=[(4
5 |
9 |
4 |
9 |
=[8+0.8]×1.25,
=8×1.25+0.8×1.25,
=10+1,
=11;
(3)12×(
1 |
60 |
1 |
17 |
=12×
1 |
60 |
1 |
17 |
1 |
17 |
=
1 |
5 |
1 |
17 |
=
1 |
5 |
1 |
17 |
=
1 |
5 |
=1
1 |
5 |
(4)3-
1993+1992×1994 |
1993×1994-1 |
=3-
1993+(1993-1)×1994 |
1993×1994-1 |
=3-
1993+1993×1994-1994 |
1993×1994-1 |
=3-
1993×1994-1 |
1993×1994-1 |
=3-1,
=2.
点评:此题考查了学生对四则混合运算顺序的掌握,以及灵活简算的能力.
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