题目内容
解方程 x-
|
x÷
| ||||||||
x÷
|
| ||||||||
x÷
|
分析:(1)先化简方程,再依据等式的性质,方程两边同时除以
求解,
(2)依据等式的性质,方程两边同时乘
求解,
(3)依据等式的性质,方程两边同时减
,再同时除以
求解,
(4)依据等式的性质,方程两边同时除以
求解,
(5)依据等式的性质,方程两边同时乘
求解.
1 |
4 |
(2)依据等式的性质,方程两边同时乘
3 |
8 |
(3)依据等式的性质,方程两边同时减
1 |
5 |
7 |
5 |
(4)依据等式的性质,方程两边同时除以
2 |
3 |
(5)依据等式的性质,方程两边同时乘
1 |
4 |
解答:解:(1)x-
x=
x=
x÷
=
÷
x=1
;
(2)x÷
=
x÷
×
=
×
x=
;
(3)x÷
+
=
x÷
+
-
=
-
x÷
×
=
×
x=1
;
(4)
x=7
x÷
=7÷
x=10
;
(5)x÷
=
x÷
×
=
×
x=
.
3 |
4 |
3 |
10 |
1 |
4 |
3 |
10 |
1 |
4 |
1 |
4 |
3 |
10 |
1 |
4 |
x=1
1 |
5 |
(2)x÷
3 |
8 |
4 |
9 |
x÷
3 |
8 |
3 |
8 |
4 |
9 |
3 |
8 |
x=
1 |
6 |
(3)x÷
7 |
5 |
1 |
5 |
4 |
5 |
x÷
7 |
5 |
1 |
5 |
1 |
5 |
4 |
5 |
1 |
5 |
x÷
7 |
5 |
7 |
5 |
3 |
5 |
7 |
5 |
x=1
1 |
25 |
(4)
2 |
3 |
2 |
3 |
2 |
3 |
2 |
3 |
x=10
1 |
2 |
(5)x÷
1 |
4 |
9 |
10 |
x÷
1 |
4 |
1 |
4 |
9 |
10 |
1 |
4 |
x=
9 |
40 |
点评:本题主要考查学生依据等式的性质解方程的能力,解方程时注意对齐等号.
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