题目内容
解方程:
x=
0.75x÷
=3
x-
x=27
14
÷x=
.
3 |
4 |
6 |
5 |
0.75x÷
1 |
3 |
x-
2 |
5 |
14
1 |
4 |
3 |
8 |
分析:(1)根据等式的性质,在方程两边同时除以
求解,
(2)根据等式的性质,在方程两边同时乘以
,再同时除以0.75求解,
(3)先化简,再根据等式的性质,在方程两边同时除以
求解,
(4)根据等式的性质,在方程两边同时乘以x,再同时除以
求解.
3 |
4 |
(2)根据等式的性质,在方程两边同时乘以
1 |
3 |
(3)先化简,再根据等式的性质,在方程两边同时除以
3 |
5 |
(4)根据等式的性质,在方程两边同时乘以x,再同时除以
3 |
8 |
解答:解:(1)
x=
,
x÷
=
÷
,
x=
;
(2)0.75x÷
=3,
0.75x÷
×
=3×
,
0.75x=1,
0.75x÷0.75=1÷0.75,
x=
;
(3)x-
x=27,
x=27,
x÷
=27÷
,
x=45;
(4)
÷x=
,
÷x×x=
×x,
=
x,
÷
=
x÷
,
x=
.
3 |
4 |
6 |
5 |
3 |
4 |
3 |
4 |
6 |
5 |
3 |
4 |
x=
8 |
5 |
(2)0.75x÷
1 |
3 |
0.75x÷
1 |
3 |
1 |
3 |
1 |
3 |
0.75x=1,
0.75x÷0.75=1÷0.75,
x=
4 |
3 |
(3)x-
2 |
5 |
3 |
5 |
3 |
5 |
3 |
5 |
3 |
5 |
x=45;
(4)
1 |
4 |
3 |
8 |
1 |
4 |
3 |
8 |
1 |
4 |
3 |
8 |
1 |
4 |
3 |
8 |
3 |
8 |
3 |
8 |
x=
2 |
3 |
点评:本题考查了学生根据等式的性质解答方程的能力,注意等号对齐.
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