题目内容
用简便方法计算:
|
36×(
|
|
(
|
分析:(1)根据乘法交换律和结合律进行计算,
(2)根据乘法分配律进行计算,
(3)根据减法的性质,先算括号里面的,
(4)先算括号里的,再算除法.
(2)根据乘法分配律进行计算,
(3)根据减法的性质,先算括号里面的,
(4)先算括号里的,再算除法.
解答:解:(1)
×
×1
×
,
=(
×
)×(
×
),
=1×1,
=1;
(2)36×(
-
),
=36×
-36×
,
=15-6,
=9.
(3)
÷(3-
-
),
=
÷[3-(
+
)],
=
÷[3-1],
=
÷2,
=
.
(4)(
-
)÷
,
=
×
,
=
.
5 |
7 |
9 |
8 |
2 |
5 |
8 |
9 |
=(
5 |
7 |
7 |
5 |
9 |
8 |
8 |
9 |
=1×1,
=1;
(2)36×(
5 |
12 |
1 |
6 |
=36×
5 |
12 |
1 |
6 |
=15-6,
=9.
(3)
1 |
4 |
5 |
13 |
8 |
13 |
=
1 |
4 |
5 |
13 |
8 |
13 |
=
1 |
4 |
=
1 |
4 |
=
1 |
8 |
(4)(
5 |
6 |
2 |
3 |
10 |
9 |
=
1 |
6 |
9 |
10 |
=
3 |
20 |
点评:本题主要考查了学生在计算中灵活运用简便算法的计算能力.
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