题目内容
12.2个$\frac{1}{5}$加上3个$\frac{1}{5}$的结果是1,$\frac{1}{7}$比$\frac{4}{7}$少3个$\frac{1}{7}$.分析 (1)先算2个$\frac{1}{5}$,用1减去所得的积,然后再除以$\frac{1}{5}$即可;
(2)先算$\frac{4}{7}$减去$\frac{1}{7}$的差,所得的差再除以$\frac{1}{7}$即可.
解答 解:(1)(1-$\frac{1}{5}$×2)÷$\frac{1}{5}$
=(1-$\frac{2}{5}$)÷$\frac{1}{5}$
=$\frac{3}{5}$÷$\frac{1}{5}$
=3
答:2个$\frac{1}{5}$加上3个$\frac{1}{5}$的结果是1.
(2)($\frac{4}{7}$-$\frac{1}{7}$)÷$\frac{1}{7}$
=$\frac{3}{7}$÷$\frac{1}{7}$
=3,.
答:$\frac{1}{7}$比$\frac{4}{7}$少3个$\frac{1}{7}$.
故答案为:3,3.
点评 本题关键是弄清运算顺序,然后再列式解答.
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