题目内容
能用简便方法的用简便方法计算.
105×32-3232÷32
125×3
×0.8×
(
-
)× 63-
210.5×[(6.05-3.35)÷1.5]
(
-
)×
÷
0.75×16+
×5-75%.
105×32-3232÷32
125×3
1 |
3 |
3 |
10 |
(
1 |
7 |
1 |
9 |
2 |
3 |
210.5×[(6.05-3.35)÷1.5]
(
5 |
6 |
3 |
4 |
2 |
5 |
1 |
2 |
0.75×16+
3 |
4 |
分析:(1)把32看作30+2,根据乘法分配律求出105×(30+2)=3150+210,同时计算出3232÷32=101,然后通过拆项和加法结合律简算;
(2)运用乘法交换律和结合律简算;
(3)运用乘法分配律计算(
-
)×63,然后与
相减即可;
(4)按运算顺序进行计算,先算小括号内的减法,再算中括号内的除法,最后算括号外的乘法;
(5)把除法改为乘法,然后按运算顺序计算,此题应注意约分;
(6)把分数和百分数化为小数,用乘法分配的逆运算简算.
(2)运用乘法交换律和结合律简算;
(3)运用乘法分配律计算(
1 |
7 |
1 |
9 |
2 |
3 |
(4)按运算顺序进行计算,先算小括号内的减法,再算中括号内的除法,最后算括号外的乘法;
(5)把除法改为乘法,然后按运算顺序计算,此题应注意约分;
(6)把分数和百分数化为小数,用乘法分配的逆运算简算.
解答:解:(1)105×32-3232÷32,
=3360-101,
=3159;
(2)125×3
×0.8×
,
=125×0.8×(
×
),
=100×1,
=100;
(3)(
-
)×63-
,
=
×63-
×63-
,
=9-7-
,
=2-
,
=1
;
(4)210.5×[(6.05-3.35)÷1.5],
=210.5×[(6.05-3.35)÷1.5],
=210.5×[2.7÷1.5],
=210.5×1.8,
=378.9;
(5)(
-
)×
÷
,
=(
-
)×
×2,
=
×
×2,
=
;
(6)0.75×16+
×5-75%,
=0.75×16+0.75×5-0.75,
=(16+5-1)×0.75,
=20×0.75,
=15.
=3360-101,
=3159;
(2)125×3
1 |
3 |
3 |
10 |
=125×0.8×(
10 |
3 |
3 |
10 |
=100×1,
=100;
(3)(
1 |
7 |
1 |
9 |
2 |
3 |
=
1 |
7 |
1 |
9 |
2 |
3 |
=9-7-
2 |
3 |
=2-
2 |
3 |
=1
1 |
3 |
(4)210.5×[(6.05-3.35)÷1.5],
=210.5×[(6.05-3.35)÷1.5],
=210.5×[2.7÷1.5],
=210.5×1.8,
=378.9;
(5)(
5 |
6 |
3 |
4 |
2 |
5 |
1 |
2 |
=(
10 |
12 |
9 |
12 |
2 |
5 |
=
1 |
12 |
2 |
5 |
=
1 |
15 |
(6)0.75×16+
3 |
4 |
=0.75×16+0.75×5-0.75,
=(16+5-1)×0.75,
=20×0.75,
=15.
点评:此题考查了学生对四则混合运算顺序的掌握,以及运用运算定律简算的能力.
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