题目内容
求未知数X.
(1)
X×(
+0.4)=4.32
(2)X÷3+X÷2=16.
解:(1)
X×(
+0.4)=4.32,
X×
=4.32,
X×
=4.32
,
X=4.8,
X
=4.8
,
X=6;
(2)X÷3+X÷2=16,
X=16,
X
=16
,
X=19.2.
分析:(1)先化简方程,再根据等式性质,两边同时除以
,再同时除以
解答,
(2)先化简方程,再根据等式性质,两边同时除以
解答.
点评:本题主要考查学生依据等式性质解方程的能力.

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X=6;
(2)X÷3+X÷2=16,

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X=19.2.
分析:(1)先化简方程,再根据等式性质,两边同时除以


(2)先化简方程,再根据等式性质,两边同时除以

点评:本题主要考查学生依据等式性质解方程的能力.

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