题目内容
用递等式计算. (1)0.48+10.8÷0.36×0.54 | (2)[9.08-(0.61+1.75)]+3.2 |
(3)![]() | (4)![]() |
解:(1)0.48+10.8÷0.36×0.54,
=0.48+30×0.54,
=0.48+16.2,
=16.68;
(2)[9.08-(0.61+1.75)]+3.2,
=[9.08-2.36]+3.2,
=6.72+3.2,
=9.92;
(3)
-
÷
+
,
=
-
×
+
,
=
-
+
,
=
+
,
=
;
(4)
÷[(
-
)÷
],
=
÷[
÷
],
=
÷[
×
],
=
÷
,
=
×
,
=6.
分析:(1)先算除法和乘法,再算加法;
(2)(4)先算小括号内的,再算中括号内的,最后算括号外的;
(3)先算除法,再算减法和加法.
点评:用递等式计算,特别注意运算顺序和运算法则.
=0.48+30×0.54,
=0.48+16.2,
=16.68;
(2)[9.08-(0.61+1.75)]+3.2,
=[9.08-2.36]+3.2,
=6.72+3.2,
=9.92;
(3)




=




=



=


=

(4)




=



=



=


=


=6.
分析:(1)先算除法和乘法,再算加法;
(2)(4)先算小括号内的,再算中括号内的,最后算括号外的;
(3)先算除法,再算减法和加法.
点评:用递等式计算,特别注意运算顺序和运算法则.

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