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       2x-$\frac{1}{5}$+$\frac{1}{5}$=$\frac{4}{5}$+$\frac{1}{5}$
            2x=1
         2x¡Â2=1¡Â2
             x=$\frac{1}{2}$£»

£¨2£©$\frac{1}{4}$x+$\frac{2}{4}$x=$\frac{7}{6}$
        $\frac{3}{4}$x=$\frac{7}{6}$
    $\frac{3}{4}$x¡Â$\frac{3}{4}$=$\frac{7}{6}$¡Â$\frac{3}{4}$
         x=$\frac{14}{9}$£»

£¨3£©x¡Â$\frac{5}{7}$=$\frac{4}{5}$
  x¡Â$\frac{5}{7}$¡Á$\frac{5}{7}$=$\frac{4}{5}$¡Á$\frac{5}{7}$
        x=$\frac{4}{7}$£»

£¨4£©$\frac{1}{2}$x-$\frac{1}{4}$=$\frac{3}{5}$
  $\frac{1}{2}$x-$\frac{1}{4}$+$\frac{1}{4}$=$\frac{3}{5}$+$\frac{1}{4}$
       $\frac{1}{2}$x=$\frac{17}{20}$
    $\frac{1}{2}$x$¡Â\frac{1}{2}$=$\frac{17}{20}$$¡Â\frac{1}{2}$
        x=1.7£»

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          $\frac{6}{7}$x=1
       $\frac{6}{7}$x$¡Â\frac{6}{7}$=1$¡Â\frac{6}{7}$
           x=$\frac{7}{6}$£®

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