题目内容
.
解:(1)
-
x=
,
-
x
x=
+
x,
-
=
+
x-
,
=
x,
=
x
,
x=
;
(2)
=
,
(1.5x-3)×2=(x-3)×5,
3x-6+15=5x-15+15,
3x+9-3x=5x-3x,
9=2x,
9÷2=2x÷2,
x=4.5.
分析:(1)依据等式的性质,方程两边同时加
x再同时减
,最后同时除以
求解,
(2)根据比例基本性质,两内项之积等于两外项之积,化简方程,再依据等式的性质,方程两边同时加15,再同时减3x,最后同时除以2求解.
点评:本题主要考查学生依据等式的性质,以及比例基本性质解方程的能力,解方程时注意对齐等号.
![](http://thumb.1010pic.com/pic5/latex/14.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/14.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/10368.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/14.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/5193.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/219182.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/182079.png)
x=
![](http://thumb.1010pic.com/pic5/latex/3724.png)
(2)
![](http://thumb.1010pic.com/pic5/latex/219183.png)
![](http://thumb.1010pic.com/pic5/latex/259.png)
(1.5x-3)×2=(x-3)×5,
3x-6+15=5x-15+15,
3x+9-3x=5x-3x,
9=2x,
9÷2=2x÷2,
x=4.5.
分析:(1)依据等式的性质,方程两边同时加
![](http://thumb.1010pic.com/pic5/latex/13.png)
![](http://thumb.1010pic.com/pic5/latex/96.png)
![](http://thumb.1010pic.com/pic5/latex/13.png)
(2)根据比例基本性质,两内项之积等于两外项之积,化简方程,再依据等式的性质,方程两边同时加15,再同时减3x,最后同时除以2求解.
点评:本题主要考查学生依据等式的性质,以及比例基本性质解方程的能力,解方程时注意对齐等号.
![](http://thumb2018.1010pic.com/images/loading.gif)
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