题目内容
(2013?道里区模拟)
简算 0.45×201 |
1.6×55.4-55.4×0.6 |
5.8+2.49+8.51+4.2 | 1.25×0.32×2.5. |
分析:(1)可将201拆分为200+1后根据乘法分配律计算;
(2)可根据乘法分配律计算;
(3)本题可根据加法交换律及结合律计算;
(4)可将0.32拆分为0.8×0.4后根据乘法结合律计算.
(2)可根据乘法分配律计算;
(3)本题可根据加法交换律及结合律计算;
(4)可将0.32拆分为0.8×0.4后根据乘法结合律计算.
解答:解:(1)0.45×201,
=0.45×(200+1),
=0.45×200+0.45×1,
=90+0.45,
=90.45;
(2)1.6×55.4-55.4×0.6,
=(1.6-0.6)×55.4,
=1×55.4,
=55.4;
(3)5.8+2.49+8.51+4.2,
=(5.8+4.2)+(2.49+8.51),
=10+11,
=21;
(4)1.25×0.32×2.5,
=1.25×0.8×0.4×2.5,
=(1.25×0.8)×(0.4×2.5),
=1×1,
=1.
=0.45×(200+1),
=0.45×200+0.45×1,
=90+0.45,
=90.45;
(2)1.6×55.4-55.4×0.6,
=(1.6-0.6)×55.4,
=1×55.4,
=55.4;
(3)5.8+2.49+8.51+4.2,
=(5.8+4.2)+(2.49+8.51),
=10+11,
=21;
(4)1.25×0.32×2.5,
=1.25×0.8×0.4×2.5,
=(1.25×0.8)×(0.4×2.5),
=1×1,
=1.
点评:完成本题要注意分析式中数据,然后运用合适的方法计算.
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