题目内容
(2012?淮安模拟)计算
1.5×[0.02÷(2.1-2.09)]
÷[
-(
-
)].
1.5×[0.02÷(2.1-2.09)]
9 |
36 |
3 |
4 |
7 |
16 |
1 |
4 |
分析:(1)依据四则运算计算方法,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的解答,
(2)先运用减法的性质,再运用加法交换律,最后依据四则运算计算方法解答.
(2)先运用减法的性质,再运用加法交换律,最后依据四则运算计算方法解答.
解答:解:(1)1.5×[0.02÷(2.1-2.09)],
=1.5×[0.02÷0.01],
=1.5×2,
=3;
(2)
÷[
-(
-
)],
=
÷[
-
+
],
=
÷[1-
],
=
÷
,
=
.
=1.5×[0.02÷0.01],
=1.5×2,
=3;
(2)
9 |
36 |
3 |
4 |
7 |
16 |
1 |
4 |
=
9 |
36 |
3 |
4 |
7 |
16 |
1 |
4 |
=
9 |
36 |
7 |
16 |
=
9 |
36 |
9 |
16 |
=
4 |
9 |
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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