题目内容
递等式计算,能简便的用简便方法.
×(
÷
)
87×
[1-(
×
)]÷
.
5 |
9 |
3 |
4 |
1 |
10 |
87×
3 |
86 |
[1-(
1 |
4 |
3 |
8 |
1 |
4 |
分析:(1)先算小括号里的除法,再算括号外的乘法;
(2)把87化成86+1,再运用乘法的分配律进行简算;
(3)先算小括号里的乘法,再算中括号里的减法,最后算括号外的除法.
(2)把87化成86+1,再运用乘法的分配律进行简算;
(3)先算小括号里的乘法,再算中括号里的减法,最后算括号外的除法.
解答:解:(1)
×(
÷
)
=
×
=
(2)87×
=(86+1)×
=86×
+1×
=3+
=3
(3)[1-(
×
)]÷
=[1-
]÷
=
÷
=
5 |
9 |
3 |
4 |
1 |
10 |
=
5 |
9 |
15 |
2 |
=
25 |
6 |
(2)87×
3 |
86 |
=(86+1)×
3 |
86 |
=86×
3 |
86 |
3 |
86 |
=3+
3 |
86 |
=3
3 |
86 |
(3)[1-(
1 |
4 |
3 |
8 |
1 |
4 |
=[1-
3 |
32 |
1 |
4 |
=
29 |
32 |
1 |
4 |
=
29 |
8 |
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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