题目内容

递等式计算(能简便的要简便).
(3618÷18-145)×20 4.2÷
2
3
×
1
7
-0.5
8.375+
5
13
-
3
8
+
2
13
5
6
×37-19÷
6
5
11
18
÷[2-(
1
4
+
5
6
)]
(2-
3
4
×
4
5
)÷(
1
12
+
4
15
分析:(1)先算括号内的除法,再算括号内的减法,最后算乘法;
(2)把除法改为乘法,约分计算,最后算减法;
(3)运用加法交换律与结合律简算;
(4)把除法改为乘法,运用乘法分配律简算;
(5)先算小括号内的,再算中括号内的,最后算括号外的;
(6)两个括号内的同时计算,第一个括号先算乘法,再算减法.
解答:解:(1)(3618÷18-145)×20,
=(201-145)×20,
=56×20,
=(50+6)×20,
=1000+120,
=1120;

(2)4.2÷
2
3
×
1
7
-0.5,
=4.2×
3
2
×
1
7
-0.5,
=0.9-0.5,
=0.4;

(3)8.375+
5
13
-
3
8
+
2
13

=(8.375-
3
8
)+(
5
13
+
2
13
),
=(8.375-0.375)+
7
13

=8+
7
13

=8
7
13


(4)
5
6
×37-19÷
6
5

=
5
6
×37-19×
5
6

=
5
6
×(37-19),
=
5
6
×18,
=15;

(5)
11
18
÷[2-(
1
4
+
5
6
)],
=
11
18
÷[2-
13
12
],
=
11
18
÷
11
12

=
11
18
×
12
11

=
2
3


(6)(2-
3
4
×
4
5
)÷(
1
12
+
4
15
),
=(2-
3
5
)÷
7
20

=
7
5
×
20
7

=4.
点评:考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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