题目内容
用递等式计算下面各题. 1.22×30÷0.15= |
0.25×7200×0.4= |
3.25÷2.5×1.2= | (40-7.36-0.64)÷0.8= |
分析:(1)同级运算,按照从左向右的顺序计算;
(2)运用乘法交换律,进行简算;
(3)同级运算,按照从左向右的顺序计算;
(4)先运用减法的性质计算出括号里的,然后除以0.8即可.
(2)运用乘法交换律,进行简算;
(3)同级运算,按照从左向右的顺序计算;
(4)先运用减法的性质计算出括号里的,然后除以0.8即可.
解答:解:(1)1.22×30÷0.15
=36.6÷0.15
=244;
(2)0.25×7200×0.4
=0.25×0.4×7200
=0.1×7200
=720;
(3)3.25÷2.5×1.2
=1.3×1.2
=1.56;
(4)(40-7.36-0.64)÷0.8
=[40-(7.36+0.64)]÷0.8
=32÷0.8
=40.
=36.6÷0.15
=244;
(2)0.25×7200×0.4
=0.25×0.4×7200
=0.1×7200
=720;
(3)3.25÷2.5×1.2
=1.3×1.2
=1.56;
(4)(40-7.36-0.64)÷0.8
=[40-(7.36+0.64)]÷0.8
=32÷0.8
=40.
点评:此类题目要注意分析算式的特点,灵活地运用定律简算.
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