题目内容

【题目】(遂昌县)用递等式计算.

①[1﹣(+]×36

②(+)×36

③7.5×4.7+4.7×2.5

④25.3×12﹣33.46÷0.35

×[÷(1﹣]

+()÷

【答案】;②29;③47;④208;4

【解析】

试题分析:①④⑤⑥根据四则混合运算的运算顺序计算即可.

②③可据乘法分配律进行计算;

解答:解:①[1﹣(+]×36,

=[1﹣(+]×36,

=[1﹣]×36,

=×36,

=

②(+)×36,

=36×

=8+21,

=29;

③7.5×4.7+4.7×2.5,

=4.7×(7.5+2.5),

=4.7×10,

=47;

④25.3×12﹣33.46÷0.35,

=303.6﹣95.6,

=208;

×[÷(1﹣]

=×[÷]

=[]

=×5,

=4

+()÷

=+()×2,

=+×2,

=+

=

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