题目内容
用递等式计算．
（1）406+4480÷28
（2）17
-1
-1
（3）
÷（
-
）×5.5
（4）
÷
+
×
（5）5-（
+
）×30
（6）[1
-（2.5-1
）]÷
．
（1）406+4480÷28
（2）17
| 5 |
| 7 |
| 8 |
| 9 |
| 5 |
| 7 |
（3）
| 3 |
| 8 |
| 7 |
| 8 |
| 1 |
| 4 |
（4）
| 1 |
| 3 |
| 5 |
| 4 |
| 2 |
| 3 |
| 4 |
| 5 |
（5）5-（
| 1 |
| 12 |
| 1 |
| 15 |
（6）[1
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 8 |
（1）406+4480÷28，
=406+160，
=566；
（2）17
| 5 |
| 7 |
| 8 |
| 9 |
| 5 |
| 7 |
=17
| 5 |
| 7 |
| 5 |
| 7 |
| 8 |
| 9 |
=16-1
| 8 |
| 9 |
=14
| 1 |
| 9 |
（3）
| 3 |
| 8 |
| 7 |
| 8 |
| 1 |
| 4 |
=
| 3 |
| 8 |
| 5 |
| 8 |
=
| 3 |
| 5 |
=3.3；
（4）
| 1 |
| 3 |
| 5 |
| 4 |
| 2 |
| 3 |
| 4 |
| 5 |
=
| 1 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 4 |
| 5 |
=（
| 1 |
| 3 |
| 2 |
| 3 |
| 4 |
| 5 |
=1×
| 4 |
| 5 |
=
| 4 |
| 5 |
（5）5-（
| 1 |
| 12 |
| 1 |
| 15 |
=5-（
| 1 |
| 12 |
| 1 |
| 15 |
=5-（2.5+2），
=5-4.5，
=0.5；
（6）[1
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 8 |
=[1
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 8 |
=[1
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 8 |
=[3-2.5]÷
| 1 |
| 8 |
=0.5÷
| 1 |
| 8 |
=4．
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