题目内容
计算下面各题.(能简便的就简便)
|
(
|
|
12÷
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|
|
(
|
|
分析:(1)(2)(7)运用乘法分配律解答,
(3)(4)运用乘法交换律解答,
(5)运用除法性质即可解答,
(6)按照从左到右顺序计算即可解答,
(8)按照先算括号里面的,再算括号外面的顺序计算即可解答.
(3)(4)运用乘法交换律解答,
(5)运用除法性质即可解答,
(6)按照从左到右顺序计算即可解答,
(8)按照先算括号里面的,再算括号外面的顺序计算即可解答.
解答:解:(1)
×14+
=
×(14+1)
=
×15
=7;
(2)(
+
)÷
=
×2+
×2
=
+
=1
;
(3)
×14×
=
×
×14
=
×14
=2;
(4)12÷
×
=12×
÷
=5÷
=6;
(5)
÷
÷
=
÷(
×
)
=
÷
=49;
(6)
÷
×
=
×
=
;
(7)(
+
)÷
=
÷
=1
;
(8)
×(
-
)
=
×
=
.
7 |
15 |
7 |
15 |
=
7 |
15 |
=
7 |
15 |
=7;
(2)(
7 |
12 |
1 |
24 |
1 |
2 |
=
7 |
12 |
1 |
24 |
=
7 |
6 |
1 |
12 |
=1
1 |
4 |
(3)
9 |
28 |
4 |
9 |
=
9 |
28 |
4 |
9 |
=
1 |
7 |
=2;
(4)12÷
5 |
6 |
5 |
12 |
=12×
5 |
12 |
5 |
6 |
=5÷
5 |
6 |
=6;
(5)
14 |
5 |
2 |
5 |
1 |
7 |
=
14 |
5 |
2 |
5 |
1 |
7 |
=
14 |
5 |
2 |
35 |
=49;
(6)
1 |
4 |
5 |
6 |
5 |
12 |
=
3 |
10 |
5 |
12 |
=
1 |
8 |
(7)(
5 |
14 |
5 |
7 |
6 |
7 |
=
15 |
14 |
6 |
7 |
=1
1 |
4 |
(8)
1 |
3 |
4 |
5 |
5 |
7 |
=
1 |
3 |
3 |
35 |
=
1 |
35 |
点评:本题考查知识点:(1)正确运用简便方法解决问题,(2)依据四则运算计算方法正确进行计算.
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