摘要:19.(I)设.
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(I)设a>0,b>0求证:a3+b3≥a2b+ab2
(II)设a>0,b>0,c>0,且a,b,c不且相等,求证:lg
+lg
+lg
>lga+lgb+lgc.
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(II)设a>0,b>0,c>0,且a,b,c不且相等,求证:lg
a+b |
2 |
b+c |
2 |
c+a |
2 |
网址:http://m.1010jiajiao.com/timu_id_68704[举报]
a+b |
2 |
b+c |
2 |
c+a |
2 |